Which expression is equivalent to 36 + 42 ?

The legend on a map states that

dimulka [17.4K]

Answer:

Step-by-step explanation:

1 cm=10 km

8 cm=10×8=80 km

4 0

3 years ago

The area of a square for on a scale drawing of 100 square centimeters and the scale drawing to 1 cm: 2 feet what is the area of

lilavasa [31]

Answer:

1. $\boxed{\text{400 ft}^{2}}$ ; 2. $\boxed{\frac{1}{3716}}$

Step-by-step explanation:

Step 1. Calculate the area of the floor

If the area A₁ of a square floor on the scale drawing is 100 cm², the length of a side is 10 cm.

The side length l of the actual floor is

l = 10 cm × (2 ft/1 cm) = 20 ft

The area A₂ of the floor is

A = l² = (20 ft)² = $\boxed{\text{400 ft}^{2}}\\$

Step 2. Calculate the area ratios

We must express both areas in the same units.

Let's express the area of the room in square centimetres.

l = 20 ft × (12 in/1 ft) = 240 in

l = 240 in × (2.54 cm/1 in) = 609.6 cm

A₂ = l² = (609.6 cm)² = 371 612 cm²

The area A₁ on the scale drawing is 100 cm².

The ratio of the areas is

$\frac{A_{1}}{ A_{2}} = \frac{100}{371612} = \frac{1 }{3716}\\$

The ratio of the area in the drawing to the actual area is $\boxed{\frac{1}{3716}}$

8 0

3 years ago

The perimeter of this triangle is 25 units. An angle bisector divides one side of the triangle into lengths of 2 and 3. Find the

grin007 [14]

Answer:

8 and 12

Step-by-step explanation:

Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means

AC/AB = CD/BD = 2/3

The perimeter is the sum of the side lengths, so is ...

25 = AB + BC + AC

25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.

20 = 5/3·AB

12 = AB

AC = 2/3·12 = 8

_____

<em>Alternate solution</em>

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).

The remaining sides of the triangle are AB=12 and AC=8.