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Solnce55 [7]
3 years ago
11

Which expression is equivalent to 36 + 42 ?

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0
It’s is option D hope this helped
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What is the value of the 4 ten times the value of 26,854
bulgar [2K]

Answer:

115416 is you answer!!!!!!!!!!!!!!!!!

Step-by-step explanation:

8 0
3 years ago
If 2X +3 equals 11 what is 4X hint solve for x first
Aleksandr [31]

Answer:

16

Step-by-step explanation:

2x+3 = 11

2x= 8

x = 4

4(x) = 4(4) = 16

7 0
3 years ago
On Monday, during a one day sale, the price of a suit was decreased by 20%. On Tuesday, the price of the suit was changed back t
nignag [31]

Answer:

25%

Step-by-step explanation:

If we consider the original price of the piece of suit is x.

Given that, on Monday during a one day sale, the price of the suit was decreased by 20%.

Therefore, the new price of the suit on Monday is x( 1 - \frac{20}{100}) = 0.8x.

Now, the price of the suit on Tuesday was changed back to the original price i.e. x.

Therefore, the price is increase by (x - 0.8x) = 0.2x from the price of 0.8x.

So, the percentage change in price of the suit on Tuesday is \frac{0.2x}{0.8x} \times 100 = 25%. (Answer)

8 0
3 years ago
Helpppp please ?????
BlackZzzverrR [31]
A) <DAE = 180-126 = 54
b) <EBC = 90 - 48 = 42
c) <BAE = 180-48-54=78
8 0
3 years ago
The National Cancer Institute estimates that 3.65% of women in their 60s get breast cancer. A mammogram can typically identify c
masha68 [24]

Answer:

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Positive test.

Event B: Having breast cancer.

3.65% of women in their 60s get breast cancer

This means that P(B) = 0.0365

A mammogram can typically identify correctly 85% of cancer cases

This means that P(A|B) = 0.85

Probability of a positive test.

85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So

P(A) = 0.85*0.0365 + 0.05*0.9635 = 0.0792

What is the probability that a woman in her 60s who has a positive test actually has breast cancer?

P(B|A) = \frac{0.0365*0.85}{0.0792} = 0.3917

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

7 0
3 years ago
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