Answer:
(Véase la explicación para mayores detalles/See the explanation for further details)
Step-by-step explanation:
a) Tres al cubo (Three to cube):
b) Seis al cubo (Six to cube):
c) Cinco al cuadrado (Five squared):
d) Ocho al cuadrado (Eight squared):
e) Dos a la quinta (Two to five):
f) Diez a la cuarta (Ten to four):
W + 3 3/8 = 1 5/6;
W = 1 5/6 - 3 3/8;
W = 11/6 - 27/8;
W = 11/(2*3) - 27/(2*4);
W = (11*4 - 27*3)/(2*3*4);
W = (44 - 81)/24;
W = -37/24 = -1 13/24;
Answer:
D-70.81
Step-by-step explanation:
I did the math, this should be correct.
Good luck!
You have some unknown integer
, and you know that adding this and the next two integers,
and
, gives a total of 57.
This means
The task is to find all three unknown integers. Notice that if you know the value of
, then you pretty much know the value of the other three integers.
To find
, solve the equation above:
So if 18 is the first integer, then others must be 19 and 20.
To find out if they are parallel we need to see if the gradient is the same, to do this we need to get y in terms of x:
assuming the first equation is x+y+7=0
y=-x-7
and
y=x-3
The gradient is the coefficient of x (the number infront of x)
For equation 1 the gradient is -1, and for number 2 it is 1, therefore they are not parallel.
However to check if they are perpendicular we need to see if their gradients multiply to equal -1.
-1*1=-1 therefore they are perpendicular
