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sweet-ann [11.9K]
3 years ago
5

To place and as in a newspaper, it cost $8 plus $0.75 for each line. Write and evaluate an expression to find the total cost for

an ad that has 6 lines. Then make a table showing the cost of there are 6,10,14, and 18 lines in the ad
Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

.75x + 8 = y (x being the number of lines) (8 being the initial charge) Then substitute x with any of the numbers above (multiply 0.75 with any) then add 8 dollars in the end..

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The elevator at the local mall has a weight limit of 1,800 pounds and requires that the maximum person allowance be no more than
blagie [28]

Answer: 9? I’m not sure but it seems like it’s 9 as it mentions it in the problem

4 0
2 years ago
((Pls help need then to get my grade up))
DIA [1.3K]
It's C because the equations are similar
3 0
3 years ago
Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for r
butalik [34]

The missing part of the question is show in bold format.

Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for rolling it

once. Your probability model shows a probable outcome of 1/6 for each of the numbers on the cube, 1 chance for all any of the 6 numbers.

You roll it 500 times and get the following data:

Outcome 1 2 3 4 5 6

Frequency 77 92 75 90 76 90

Exercises 1–2

1. If the equality model was correct, about how many of each outcome

would you expect to see if the cube is rolled 500 times

2. Based on the data from the 500 rolls, how often were odd numbers observed? How often were even numbers observed?

Answer:

Step-by-step explanation:

1.

If the equally likely model was correct,  about how many of each outcome

would you expect to see if the cube is rolled 500 times.

The probability of rolling any of the numbers from 1 to 6 is  p(1/6)

The number of each of the outcomes expected to be seen in 500 rolls of the number cube is np

= 500 * \frac{1}{6}  \\ \\ = \frac{500}{6} \\ \\  = 83.333 \\ \\ \approx 83

2.  From the given data in the roll;

The odd numbers 1, 3 and 5, were obtained at  77, 75 and 76 times respectively.

Thus, the total number of times odd number were rolled = 77 + 75 + 76 = 228

Probability of an odd number turning up = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{228}{500}

= 0.456

= 45.6%

The even numbers, 2, 4 and 6, were obtained 92, 90 and 90 times respectively.

The total number of times even number were rolled = 92 + 90 + 90 = 272

Probability of an even number turning up  = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{272}{500}

= 0.544

= 54.4%

4 0
3 years ago
Select the correct answer.
exis [7]
F(x)=2^x is the answer
5 0
3 years ago
Which could be the entire interval over which the function,
Marrrta [24]

Answer:

(-2, 1)

Step-by-step explanation:

Hi Juliadayx! How are you?

Well, maybe you already heard about the domain and the range of a function.  

The domain is the set of values that the independent variable can take (usually referred to as the letter "x"), while the range is the set of values that the dependent variable takes, which is called f(x) or function of x.

In this case, the exercise asks you to evaluate for which values of “x” (right column of the table), the function “f(x)” takes positive values (left column of the table), the positive values also include zero. And in this case you can see that the function f(x) is only positive for the values of "x": -2, -1, 0 and 1. Therefore, the answer is the entire interval (-2, 1).

I hope I've been helpful!

Regards!

3 0
3 years ago
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