Answer:
C) y=x^2+x-6
Step-by-step explanation:
Looking at the first picture, the equation is way too high, thus A is incorrect
Looking at the second picture, the equation is also too high, thus B is incorrect
Looking at the third picture, the equation is at the graph, thus C is correct
Looking at the fourth picture, the equation is more at the right than at the left thus the equation is incorrect
Hope this helps!
17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
Answer:
look at the graph i made with desmos, i just plugged the equation in.
Step-by-step explanation:
First solve your inequality step by step.
y+15<3
= y<-12
Answer is A. y<-12
Answer will help you.
Brainliest answer and Verified answers.
