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lora16 [44]
3 years ago
9

Which is an equation of a circle with center (2, -1) that passes through the point (3, 4)?

Mathematics
1 answer:
Reil [10]3 years ago
4 0
The equation for a circle is (x-h)^2 + (y-k)^2 = r^2. Because we have a center and a coordinate, all we have to solve for is the radius.  Fill in the equation like this: (3-2)^2 + (4+1)^2 = r^2.  That gives us 1^2 + 5^2 = r^2 and 26=r^2.  Now we use that squared radius along with the center to complete the equation for the circle: (x-2)^2 + (y+1)^2 = 26 which is #3 above.
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