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3 years ago

Given there's 5 red balls and 2 blue balls. What's the probability that after two picks we have a red ball and a blue ball

Mathematics

1 answer:

Svetach [21]3 years ago

5 0

Answer:

the answer is 58 dear because there he couldn't figure out what he meant

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Karo-lina-s [1.5K]

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7 0

3 years ago

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Alborosie

$\huge\underline\pink{✏ANSWER}$

<h2>Hello and sorry but it's a Gatheted Question Can you fix it Can you? </h2>

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#BrainliestBunch

4 0

3 years ago

Factor the expression completely.

evablogger [386]

Answer:

Factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

Step-by-step explanation:

We need to factor the expression $xy^4+x^4y^4$ completely

We need to find common terms in the expression.

Looking at the expression, we get $xy^4$ is common in both terms, so we can write:

$xy^4+x^4y^4\\=xy^4(1+x^3)$

So, taking out the common expression we get: $xy^4(1+x^3)$

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

So, we get:

$xy^4(1+x^3)\\=xy^4(x^3+1)\\Applying\:the\:formula\;of\:a^3+b^3\\=xy^4(x+1)(x^2-x+1)$

Therefor factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

6 0

3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints are

Degger [83]

Answer:

y = -2/3x - 11/3

Step-by-step explanation:

7 0

3 years ago