It looks like you want to compute the double integral
over the region <em>D</em> with the unit circle <em>x</em> ² + <em>y</em> ² = 1 as its boundary.
Convert to polar coordinates, in which <em>D</em> is given by the set
<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}
and
<em>x</em> = <em>r</em> cos(<em>θ</em>)
<em>y</em> = <em>r</em> sin(<em>θ</em>)
d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>
Then the integral is
Answer:
$ 14.00
Step-by-step explanation:
10 · 1.75 = 17.50
17.50 · .20 = 3.5
17.50 - 3.50 = 14.00
good luck, i hope this helps :)
I have returned!
36 can technically be either A or B, although A works better. The workers are trying to see which type of vegetables sell better, and it’s easier to see which bar is taller rather than which slice is bigger.
37 would be the median, or the middle of all the values. The median is 30 (two smaller and two bigger values), while the range is 27 (32-5, range of values), the mode is 5 (the value that occurs the most), and the mean is 20.6 (average of all values). The median is the only value larger than 30, so this would be the best one to tell his parents.
Multiply 4 * 5, which equals 20, and add the two zeroes(from 40 and 50) on the end.
That gives us:
2000
Answer:
A function is a relation that maps inputs from a set called the domain, into outputs from a set called the range.
Such that each input can be mapped into only one output.
So for example, if we have a relation that maps the input 2 into two different values:
f(2) = 4
f(2) = 8
Then this is not a function.
In the case of the problem, we have a student as the input, and the hair color as the output.
So we will have something like:
f(student) = blond
And if this student decides to change his/her hair color to red?
Then the function becomes:
f(student) = red
So for the same input, we had two different outputs, which means that this is not a function.
We also could have the case where a given student has two colors (Californian for example)
Where again, we would see two different outputs for one single input.
