Answer:
The equation of the line that passes through (1, 2) is y = - 2x + 4
Step-by-step explanation:
2x + y - 1 = 0
2x + y - 1 + 1 = 0 + 1
2x + y = 1
2x - 2x + y = 1
y = - 2x + 1
parallel lines have the same slope, so the equation line will be -2
plug in the point, y = mx + b (x, y)
y = (-2)x + b , (1, 2)
(2) = (-2)(1) + b
2 = -2 + b
2 + 2 = -2 + 2 + b
4 = b
y = - 2x + 4
we have
x=5−2y ---> multiply by 3 both sides-----> 3x=15-6y-----> 6y=15-3x----> equation 1
6y=10−3x------> equation 2
equation 1 and equation 2 has the same slope
the lines are parallel
slope m=-3/6-----> m=-1/2
so
there are no solution
the answer is the option
b. There is no solution
We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.
11.
Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.
tan B = b/a
b = a tan B = 65.7 tan 28.9° = 36.3 m
12.
Similar story, boat at B, opposite b=3.5 m, rope c=12 m
sin B = b/c
B = arcsin b/c = arcsin (3.5/12) = 17.0°
13.
c=124 m, A=58°
sin A = a/c
a = c sin A = 124 sin 58 = 105.2 m
14.
That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so
cos A = b/c
A = arccos b/c = arccos (1.8/2.8) = 50.0°
15.
Not a right triangle, an isosceles triangle. Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°. We're after d=2b:
sin B = b/c
b = c sin B
d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm
Almost equilateral
So, let's start off with explaining what these different questions mean;
y = |x + c| Shifts the graph c units left.
y = |x - c| Shifts the graph c units right.
y = |x| + c Shifts the graph c units up.
y = |x| - c Shifts the graph c units down.
(0,0) Is the starting point on any graph like this. So, determine the answer by going through the list of answers.
I believe the answer is y = 2x.
I would like to know if I am wrong so contact me!!
