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Andreyy89
3 years ago
13

75% of the normal price of headphones is 45$. What's the normal price?

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

Answer:

60$ is the normal price.

Why:

Because if 45$ is 75%, then 30$ is 50%, 15 is 25%, and 0 is 0%. 50% + 50% = 100%. (That's how I did this one, anyway. This works on any 25%, 50%, or 75% problem.)

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A square has a side of 6.25 feet. What is the area in square feet? Round to the correct significant digits. (2 points)
soldi70 [24.7K]

Answer:

A=39.06 Sq Ft

Step-by-step explanation:

We are given with a square which has a side of 6.25 feet. We are asked to determine the area in square feet and Round to the correct significant digits.

Area of square is given as

A= side x side

Side = 6.25 ft

A=6.25 x 6.25

A= 39.0625

Rounding it to the nearest hundredth place

A=39.06 sq ft

7 0
3 years ago
Han's garden has an area of 193.75
ycow [4]

Answer:

15.5

Step-by-step explanation:

The equation to find area is Length × Width= Area

we have the area and the length, 12.5 × width= 293.75

to find the width, you will have to reverse engineer and divide the area by the length instead.

193.75 ÷ 12.5 =15.5

just to double check, 15.5 × 12.5 = 193.75

the width is 15.5

3 0
3 years ago
Your boss calls you and explains that your first visit is to the Barclays Center Stadium. Your boss says the Barclay center is a
Nady [450]

Answer:

66.341 Feet

Step-by-step explanation:

length 819

width 818

(Length x width)

divide both by 100.5

819/100.5

818/100.5

8.14925373134

8.13930348259

round

8.15

8.14

length times width

8.15*8.14

66.341

3 0
3 years ago
? Question
uysha [10]

Answer:

B1: -9, -3, and 10

B2: 5

Step-by-step explanation:

mark brainliest

8 0
3 years ago
Denise is planning to put a deck in her back yard. The deck will be a 10-by-7-foot rectangle with a semicircle of diameter 4 fee
vladimir2022 [97]

Answer:

approx. = 85.28 {ft}^{2}

Step-by-step explanation:

You can think of this as adding the area of the rectangular portion of the deck (length x width) and the semicircular portion (πr^2)/2.

(l×w)+(πr^2)/2

(10×7)+((π2^2)/2

79+2π

approx. = 85.28 {ft}^{2}

3 0
3 years ago
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