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kari74 [83]
3 years ago
13

Solve the given third-order differential equation by variation of parameters. y''' − 5y'' − y' + 5y = e4x

Mathematics
1 answer:
sineoko [7]3 years ago
3 0
Consider, please, the attached solution.

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Find the value of x using angle properties & the measure of
Jobisdone [24]

Answer:

15.

x = 20

16.

\angle BFH = 100\textdegree

\angle CBD = 100\textdegree (if needed)

-------------------------------------------------------------------

17.

x = 7

18.

\angle BFH = 68\textdegree

Step-by-step explanation:

15. The two following angles, which is \angle CBD and \angle BFH, are <u>Corresponding Angles</u>. Write an expression by using the following measurements from  \angle CBD and  \angle BFH. Then, solve the expression for the value of x:

\angle CBD = 5x

\angle BFH = 3x + 40

5x = 3x + 40

Solve for x:

5x = 3x + 40

5x - 3x = 3x - 3x + 40

2x = 40

\frac{2x}{2} = \frac{40}{2}

x = 20

16. After you have the value x use it to find the <u>actual</u> measurements of both \angle CBD and \angle BFH, by applying x to the following expressions from both \angle CBD and \angle BFH and solve them:

-The value of x:

x = 20

-Solve for \angle CBD:

\angle CBD = 5x

5(20)

100

-The <u>actual</u> measurement of \angle CBD:

\angle CBD = 100\textdegree

-Solve for \angle BFH:

\angle BFH = 3x + 40

3(20) + 40

60 + 40

100

-The <u>actual</u> measurement of \angle BFH: (if needed)

\angle BFH = 100\textdegree

----------------------------------------------------------------------------

17. The two following angles, which is \angle BFE and \angle DBF are <u>Alternate Interior Angles</u> .Write an expression by using the following measurements from \angle BFE and \angle DBF. Then, solve the expression for the value of x:

\angle BFE = 16x

\angle DBF = 4x + 84

16x = 4x + 84

-Solve for x:

16x = 4x + 84

16x - 4x = 4x - 4x + 84

12x = 84

\frac{12x}{12} = \frac{84}{12}

x = 7

18. After you have the value x use it to find the <u>actual</u> measurement of  \angle DBF, by applying x to the expression from \angle DBF and solve it and find the actual measurement of an angle that is not labeled, which is \angle BFH:

-The value of x:

x = 7

Solve for \angle DBF:

\angle DBF = 4x + 84

4(7) + 84

28 + 84

112

-The <u>actual</u> measurement of \angle DBF:

\angle DBF = 112\textdegree

-Since both \angle DBF and \angle BFH are supplementary (two angles that equals to 180\textdegree), and you want to find the <u>actual</u> measurement of \angle BFH, Use the measurement of \angle DBF and subtract it from 180\textdegree:

\angle DBF - 180\textdegree

112\textdegree - 180\textdegree = 68\textdegree

-The <u>actual</u> measurement of \angle BFH:

\angle BFH = 68\textdegree

8 0
3 years ago
Find three consecutive odd integers such that the sum of the smaller two is three times larger increased by seven
sukhopar [10]

Answer:

three consecutive odd integers:  2n-1   2n+1   2n+3

that the sum of the smaller two is three

times larger increased by seven:                 2n-1  +  2n+1 = 3(2n+3) +7

                                                                                4n = 6n+ 9 +7

                                                                                4n = 6n+ 16

                                                                           4n -6n = 16

                                                                                -2n = 16

                                                                                   n = 16/(-2)

                                                                                   n=-8

a)   2n -1 = 2(-8) -1 = -17

b)   2n+1 = 2(-8)+1 = -15

c)   2n+1 = 2(-8)+3 = -13

Ans.   -17 ;  -15   ; -13

4 0
3 years ago
Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st
Naily [24]

Answer:

\boxed{2^{\frac{802}{27}} \cdot 3^9}

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

\text{Use } \LaTeX !

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! (*^U^)人(≧V≦*)/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

\left(\dfrac{1}{3^2}  \cdot \dfrac{1}{4^5}  \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3

Also,

\boxed{a^{0} = 1, a\neq 0 }

\left(\dfrac{1}{9}  \cdot \dfrac{1}{1024}  \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

Note

\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq  0}

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27

\left(\dfrac{1}{9216}   \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)

Note

\boxed{\dfrac{1}{\dfrac{1}{a} }  = a}

9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)

\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)

Once

9216=2^{10}\cdot 3^2 \implies  9216^3=2^{30}\cdot 3^6

\boxed{(a \cdot b)^n=a^n \cdot b^n}

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27} $

We have

\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)

Also, once

\boxed{\dfrac{c^a}{c^b}=c^{a-b}}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27

As

30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27}  =\dfrac{802}{27}

2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3

2^{\frac{802}{27}} \cdot 3^9

4 0
3 years ago
Plot the x- and y-intercepts to graph the equation. <br> y = 1/3x − 1
Trava [24]
If you have questions, feel free to ask

8 0
3 years ago
Read 2 more answers
72 is what percent of 480
VLD [36.1K]
72 is 15% of 480. if you divide 72 by 480 it gives you .15 and then you mutiply the .15 by 100
7 0
3 years ago
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