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3 years ago

When you roll a die the probability of rolling a number less than 3 is 2/6.

Mathematics

1 answer:

Lilit [14]3 years ago

3 0

2/6 I hope this answers your question

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What is the sum of -1/2 and 8/6 a) -5/6 B) -11/6 C) 5/6 D) 11/6

Leto [7]

Answer:

d 11/6

Step-by-step explanation:

find the common denominate for -1/2 which is 3/6 make sure you remember the rule of integers adding if they have diffrent sign there gonna be postive if they have the same sign there negative look up the role it will help you a lot find the common denominator which and then add like normal if it ask for it s lowest term then find the lowest term have a good day if you have question please type in the comments if you need more help

3 0

3 years ago

-4+6y=16 Change to slope (intercept)

hichkok12 [17]

*here is step by step*
(Remember to add the 'x' to the slope)

-4x+6y=16

6y=4x+16

y= 4/6x + 2.66

The complete answer is:
y= 2/3x + 2.66

7 0

3 years ago

What is the best estimate of 42% of 756? a)320 b)240 c)400 d)400

nataly862011 [7]

320 i believe... the original answer was 317.52

4 0

3 years ago

Read 2 more answers

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

Read 2 more answers

Fifteen students were divided into two classrooms in a ratio of 1:2.

IgorC [24]

The answer: In Classroom 1, there are 5 students while in Classroom 2, there are 10 students.

Explanation:
x + 2x = 3x
3x = 15
x = 5, Classroom 1 = 5, Classroom 2 = 5 x 2 = 10

I hope that this helps! :)

3 0

2 years ago