In 2007, there were more than 8.14 million cars for sale. Over the next 3 years, the number of cars decreased by 23%. Write an e xponential growth or decay model given by the number of c cars over t years after 2007. Use this model to estimate how many cars there will be in 2013?
1 answer:
Answer:
c = 8.14 million×(0.9166)^t
4.83 million
Step-by-step explanation:
Data:
t = y - 2007
c₀ = 8.14 million
c₃ = 23 % less than c₁
Part 1. Calculate c₃
c₃ = c₀(1 - 0.23) = 0.77c₀
Part 2. Calculate r
c₃ = c₀r^t
0.77c₀ = c₀r³
0.77 = r³ Divided each side by c₀
r = 0.9166 Took the cube root of each side
The explicit decay model is c = 8.14 million×(0.9166)^t
Part 3. Prediction
t = 2013 - 2007 = 6
c = c₀r^t = 8.14 million×(0.9166)⁶ = 8.14 million × 0.5929 = 4.83 million
The model predicts that there will be 4.83 million cars for sale in 2013.
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