It’s asking for X. “Find x”. I was wondering if someone could help. Thank you.

Mathematics

1 answer:

Kazeer [188]3 years ago

6 0

Answer:

what are the optionnnnnn????

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CAN SOMEONE HELP???????????

guapka [62]

Answer:

g(-1) = -1

g(-0.25) = 0

g(2) = 2

Step-by-step explanation:

6 0

3 years ago

Solve to indicated variable 16ak=-5 for a

damaskus [11]

The answer is
$\frac{ - 5}{16k} = a$
steps
#1) Try to leave a by itself by dividing any variable next to it
$\frac{16 ak = - 5 }{ 16k}$
you can only divided these variables as all these variables in the original equation. are being multiplied. The opposite if multiplication is division.

3 0

4 years ago

Solve the following system of equations graphically.

V125BC [204]

(2,1)

I first used substitution to get my answer and then used graphing to check. You can easily get a graphing equation by rearranging the second equation.<span />

4 0

4 years ago

Read 2 more answers

I'm not sure what I supposed to do there is an example to help.

Delvig [45]

Question 1:

Conclusion: ∠DAY + ∠YAK = 180°

Justification: definition of linear pair

Question 2:

Conclusion: Point U is the midpoint of RN

Justification: RU=UN, definition of midpoint

Question 4:

Conclusion: ∠3 = ∠7

Justification: definition of alternate interior angles

Question 5:

Conclusion: ∠ABD = ∠DBC

Justification: definition of bisector

Question 6:

Conclusion: ∠2 and ∠3 are supplementary angles

Justification: definition of supplementary angles

Sorry question 3, don't know what it's trying to say

8 0

3 years ago

PLEASE HELP! Find the missing part.

viktelen [127]

Answer:

Step-by-step explanation:

$\frac{y}{a}= tan~60=\sqrt{3} \\y=a\sqrt{3} ~~~(1)\\\frac{y}{b} =tan~30\\y=\frac{b}{\sqrt{3} } ~~~(2)\\from~(1)~and~(2)\\a\sqrt{3} =\frac{b}{\sqrt{3} } \\b=a\sqrt{3} \times\sqrt{3} =3a\\a+b=15\\a+3a=15\\4a=15\\a=\frac{15}{4} \\b=3a=3 \times \frac{15}{4} =\frac{45}{4}\\y=a\sqrt{3} =\frac{15\sqrt{3}}{4} \\\frac{x}{15} =sin~30\\x=15 \times \frac{1}{2}=\frac{15}{2}\\\frac{z}{15}=cos~30\\z=15 \times \frac{\sqrt{3}}{2}=\frac{15\sqrt{3} }{2} \\$

4 0

3 years ago