Since g(6)=6, and both functions are continuous, we have:
![\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2Bf%28x%29g%28x%29%5D%20%3D%2045%5C%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2B6f%28x%29%5D%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B9f%28x%29%5D%20%3D%2045%5C%5C%5C%5C9%5Ccdot%20lim_%7Bx%20%5Cto%206%7D%20f%28x%29%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20f%28x%29%3D5)
if a function is continuous at a point c, then
,
that is, in a c ∈ a continuous interval, f(c) and the limit of f as x approaches c are the same.
Thus, since
, f(6) = 5
Answer: 5
Answer:
25
Step-by-step explanation:
20*5=100%
then you multiply 5 by 5 giving you 25
Triangle 1 has vertices at (A, B), (C, D), and (E, F). Triangle 2 has vertices at (A,-B), (C,-D), and (E,-F). What can you concl
almond37 [142]
Answer:
Triangle 2 is a transformation from Triangle 1, and has been reflected across the x-axis.
Step-by-step explanation:
We can conclude that Triangle 2 is a reflection across the x-axis because the x values stayed the same but the y values are negative.
In a reflection across the x-axis, the x values will stay the same. But, since it is flipped across the x-axis, the y values will become negative.
So, Triangle 2 is a reflection across the x-axis.
Answer:
Where are the numbers?
Step-by-step explanation:
Answer:
You can go ahead with option D
Step-by-step explanation:
<h2>30% of x will be 3x</h2>
