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3 years ago

Solve the following equation y= 3/2x-50 when y=7.

Mathematics

1 answer:

gavmur [86]3 years ago

6 0

Answer:

3/2x - 50 = 7

3/2x = 57

x = 38

Step-by-step explanation:

sorry if its wrong

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A field test for a new exam was given to randomly selected seniors. The exams were graded, and the sample mean and sample standa

Radda [10]

So the fisrt thing we need to calculate is that 9 times out of 10 is 90% which will be the confidence interval.
Margin of error is 6% = .06 
Confidence interval is 80 +/- .06 = .74 to .86. or 74% to 86$ 
In 9 times out of 10 the confidence interval for similar samples of seniors will contain the true mean of the population of senior scores.

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3 years ago

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Which order pair is a solution to the system of linear equations -4+y=8 and x-5y=17?

andreev551 [17]

Hello!

To find this ordered pair, we solve for x and y and put them together in an ordered pair.

-4+y=8

x-5y=17

Let's solve the first equation for y.

y= 12

Now, let's plug 12 into the second equation for y.

x-5(12)=17

x-60=17

x=77

Therefore, our ordered pair is (77,12)

I hope this helps!

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3 years ago

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The radius of a sphere is 6 units.

skad [1K]

Answer: Four-thirdsπ(6)³

Step-by-step explanation: The formula for the volume of a sphere is attached in the image down below.

Notice that two of the options listed have three-fourths but we use four-thirds to find the volume of a sphere. This means that we can eliminate the 1st and the 3rd option.

Now, we will multiply that by π and then by the radius cubed which is also written as 6³. This means that our answer would be the second option.

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3 years ago

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Find the multiplicative inverse of 6 + 2i

Marina CMI [18]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2774989

________________

Find the multiplicative inverse of

$\mathsf{z=6+2i}$

________

The inverse multiplicative of $\mathsf{z=a+bi}$ is

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\qquad\quad(a\ne 0~~and~~b\ne 0)}\\\\\\
=\mathsf{\dfrac{1}{a+bi}\cdot \dfrac{a-bi}{a-bi}}\\\\\\
=\mathsf{\dfrac{1\cdot (a-bi)}{(a+bi)\cdot (a-bi)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-\,\diagup\hspace{-10}abi+\,\diagup\hspace{-10}abi-(bi)^2}}$

$=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot i^2}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2-b^2\cdot (-1)}}\\\\\\
=\mathsf{\dfrac{a-bi}{a^2+b^2}}\\\\\\\\
\therefore~~\mathsf{\dfrac{1}{a+bi}=\dfrac{a}{a^2+b^2}-\dfrac{b}{a^2+b^2}\,i\qquad\quad\checkmark}$

________

For this question,

$\mathsf{z=6+2i}$

So,

$\mathsf{\dfrac{1}{z}}\\\\\\
=\mathsf{\dfrac{1}{6+2i}}\\\\\\
=\mathsf{\dfrac{6}{6^2+2^2}-\dfrac{2}{6^2+2^2}\,i}\\\\\\
=\mathsf{\dfrac{6}{36+4}-\dfrac{2}{36+4}\,i}\\\\\\
=\mathsf{\dfrac{6}{40}-\dfrac{2}{40}\,i}$

$\therefore~~\mathsf{\dfrac{1}{z}=\dfrac{3}{20}-\dfrac{1}{20}\,i}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

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3 years ago

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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

fiasKO [112]

Answer: $tan(E)=1.70$

Step-by-step explanation:

For this exercise you need to remember the following Trigonometric Identity:

$tan\alpha =\frac{opposite}{adjacent}$

You must observe the figure given in the exercise.

You can notice that the given triangle EFG is a Right triangle (Right triangles are defined as those triangles that have an angle that measures 90 degrees).

So, you can identify in the figure that:

$\alpha=E\\\\ opposite=FG=56\\\\adjacent=EF=33$

So, knowing these values, you can substitute them into $tan\alpha =\frac{opposite}{adjacent}$ and then you must evaluate (Remember to round the result to the nearest hundreth).

Therefore, through this procedure you get:

$tan(E)=\frac{56}{33}\\\\tan(E)=1.70$

4 0

3 years ago