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2 years ago

Can someone please help me with this?!! and the first choose options are: linear or nonlinear

Mathematics

1 answer:

VLD [36.1K]2 years ago

6 0

Answer:

nonlinear

Step-by-step explanation:

It isn't a straight line

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I will give brainliest to right answer

gavmur [86]

Answer:

Is it A???

Step-by-step explanation:

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3 years ago

What is the unit rate for 5 pounds of lunch meat for $42.50?A. $5.31 per poundB. $6.50 per poundC. $7.25 per poundD. $8.50 per p

KengaRu [80]

Hey there! I'm happy to help!

We want to find how much money the lunch meat costs for one pound. We see that it costs $42.50 for 5 pounds, so we simply divide by 5 to see how much it costs for 1 pound.

42.5/5=8.5

Therefore, the answer is D. $8.50 per pound.

Have a wonderful day! :D

4 0

3 years ago

Read 2 more answers

What is the following sum?<br> 4(^5sqrtx^2y) + 3(^5sqrtx^2y)

Schach [20]

Answer:

option 3

Step-by-step explanation:

$(4 + 3) \sqrt[5]{x {}^{2}y } = 7 \sqrt[5]{ {x}^{2}y }$

7 0

2 years ago

Read 2 more answers

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$