The surface area of the figure given is of: 61.3 yd².
<h3>What is the combined surface area of a figure?</h3>
The combined surface area of a figure is the area of each figure.
This figure is composed by:
- A triangle with base 6 yd and one leg 11.4 yd.
The area of the circle is given as follows:

For the triangle, we need to find it's height, which is the <u>leg of a right triangle, in which one of the sides is 3 and the hypotenuse is 11.4</u>, hence:
h² + 3² = 11.4²

h = 11 yd.
Hence the area of the triangle is:
A = 0.5 x 6 x 11 = 33 yd²
The surface area of the figure is:
9pi + 33 yd² = 61.3 yd².
More can be learned about the surface area of at brainly.com/question/21208177
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Answer:
see explanation
Step-by-step explanation:
(5)
Since ∠EBA = 90° then ∠ABD = 90° ( straight angle ) and
∠ABC + ∠CBD = ∠ABD, that is
2x + 3x - 10 = 90, simplifying
5x - 10 = 90 ( add 10 to both sides )
5x = 100 ( divide both sides by 5 )
x = 20, thus
∠ABC = 2x = 2 × 20 = 40°
∠CBD = 3x - 10 = (3 × 20) - 10 = 60 - 10 = 50°
(6)
4x - 18 = 3x + 7 ( vertical angles are congruent )
Subtract 3x from both sides
x - 18 = 7 ( add 18 to both sides )
x = 25
7y = 5y + 28 ( vertical angles are congruent )
Subtract 5y from both sides
2y = 28 ( divide both sides by 2 )
y = 14
Answer:
it might be b and d
Step-by-step explanation:
Number 4 is 1
3-x = -x + 3