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uranmaximum [27]
3 years ago
14

The binomial expansion of (x + y)2 is

Mathematics
2 answers:
JulsSmile [24]3 years ago
6 0

Step-by-step explanation:

{x}^{2}  + 2xy +  {y}^{2}

yawa3891 [41]3 years ago
6 0

(x + y) ^{2}  =  {x}^{2}  + 2xy +  {y}^{2}

Answer: A

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A ball is thrown into the air from an apartment balcony and falls to the ground. The height of the ball, h metres, t seconds aft
andriy [413]

Answer:

1+2\sqrt{2} seconds

Step-by-step explanation:

When the ball hits the ground, its height will obviously be 0. Therefore, you can set up the equation the following way:

0=-5t^2+10t+35 \\\\-5(t^2-2t-7)=0

Plugging this into the quadratic equation, you get:

t=\dfrac{2\pm\sqrt{4+28}}{2}= \\\\\dfrac{2\pm4\sqrt{2}}{2}= \\\\1\pm2\sqrt{2}

Since the time must be positive, it takes the ball 1+2\sqrt{2} seconds to hit the ground, or around 3.828. Hope this helps!

7 0
3 years ago
I will use fancy gold and red wrapping paper for two packages i have to wrap. I will use 1 2/4 yard of paper for one of the boxe
Allisa [31]
Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.

You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
6 0
3 years ago
Quentin pays $178 every 4 months for his guitar lessons. At this rate , how much will Quentin pay for 3 years of guitar lessons
vivado [14]
$1602 would be the amount paid for 3 years of lessons.
7 0
3 years ago
Read 2 more answers
What is the domain and range of the relation shown in the table?
TEA [102]

Answer:

<u>domain: {10,15,19,32}</u>

<u>range:{5,9,-1}</u>

Step-by-step explanation:

  • As we know domain is the values of input and range is the values of output.
  • Here , x is the input and y is the output.
  • \left[\begin{array}{cc}x&y\\10&5\\15&9\\19&-1\\32&5\end{array}\right]
  • Thus the input values according to the given problem is : 10 ,15 , 19, and thus ,

⇒<em>The domain would accordingly be these four numbers : 10 , 15 , 19 , 32.</em>

  • <u>Note that we donot have any information regarding the other values of x.</u>
  • The range is : { 5,9,-1 } only as the 5 is repeated in two cases .
  • Range is unique and there must be not repetition. Thus the apt answer would be :

<em>domain: {10,15,19,32}</em>

<em>range:{5,9,-1}</em>

6 0
3 years ago
Solve for x by completing the square: x2 - 12x + 11 = 0
sineoko [7]

Answer:

B

Step-by-step explanation:

x² - 12x + 11 = 0 ( subtract 11 from both sides )

x² - 12x = - 11

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 6)x + 36 = - 11 + 36

(x - 6)² = 25 ( take square root of both sides )

x - 6 = ± \sqrt{25} = ± 5 ( add 6 to both sides )

x = 6 ± 5

Then

x = 6 - 5 = 1 ⇒ (1, 0 )

x = 6 + 5 = 11 ⇒ (11, 0 )

6 0
2 years ago
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