Answer:mkay, also yes he did
Step-by-step explanation:
1.Remove the parentheses
2.put -5z and 4z together which makes -9z(negative plus positive equals negative)
3.-9z+ -6z=-3z and 7+8=15
4.15 decided by -3=5
so yes, z=-5
0.0048 Decimal
3/ 625 Fraction
Answer:
Quadrilateral ABCD is not a square. The product of slopes of its diagonals is not -1.
Step-by-step explanation:
Point A is (-4,6)
Point B is (-12,-12)
Point C is (6,-18)
Point D is (13,-1)
Given that the diagonals of a square are perpendicular to each other;
We know that the product of slopes of two perpendicular lines is -1.
So, slope(m) of AC × slope(m) of BD should be equal to -1.
Slope of AC = (Change in y-axis) ÷ (Change in x-axis) = (-18 - 6) ÷ (6 - -4) = -24/10 = -2.4
Slope of BD = (Change in y-axis) ÷ (Change in x-axis) = (-1 - -12) ÷ (13 - -12) = 11/25 = 0.44
The product of slope of AC and slope of BD = -2.4 × 0.44 = -1.056
Since the product of slope of AC and slope of BD is not -1 hence AC is not perpendicular to BD thus quadrilateral ABCD is not a square.
Answer: yes it is equivalent!
Step-by-step explanation:
all you do is take away the parentheses and then it is the same exact thing!
