Find the value 9 (2) 7 HELPPPP MEEEE I NEED THIS ASAP
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Answer: (a) Job A , by approximately $69, 482
(b) Job A , by approximately $6,867
(c) Job B , by approximately $ 767,362
(d) Job A
Step-by-step explanation:
JOB B
The starting Salary is $ 10,000
Since there is an increment of 25% at the beginning of each new year. The breakdown of the increment is as follow:
First year : 125% of $ 10,000 = $12,500
Second year : 125% of $ 12,500 = $15,625
Third year : 125% of $15,625= $19,531.25
Fourth year: 125% of $19,531.25 = $24,414.06
Fifth year : 125% of $24,414.06 = $30,517.58
Sixth year: 125% of $30,517.58 = $38,147.00
Seventh year: 125% of $38,147.00 = $47,683.75
Eight year: 125% of $47,683.75 = $59,604.69
Ninth year: 125% of $59,604.69 = $74,505.86
Tenth year: 125% of $74,505.86 = $93,132.32
Following the same procedure:
Eleventh year = $116,415.40
Twelfth year = $145,519.25
Thirteenth year = $181,899.06
Fourteenth year = $227,373.82
Fifteenth year = $ 284,217.29
Sixteenth year = $355,271.61
Seventeenth year = $444,089.51
Eighteenth year = $555,111.89
Nineteenth year = $693,889.86
Twentieth year = $867,362.32
(a) Following the analysis above, at the beginning of the fifth year Job A will have a greater annual salary
Difference: Salary of Job A at the beginning of fifth year remains $ 100,000 while that of Job B resulted into $ 30,517.58, the difference implies
$100,000 - $ 30,517.58 = $69,482
(b) At the beginning of tenth year, Job A is still $100,000, Job B resulted into $93,132.32. Job A is still greater by approximately $6,867
(c) At the beginning of the twentieth year, the annual salary of A is still $ 100,000 while the annual salary of B is $ 867,362.32. Job B annual salary is greater by approximately $ 767,362
(d) If I were in Jane’s shoe I will take Job A and work for few years to gain more experience the look for a job that pays better. Waiting for many years in case of Job B is risky , market situation is uncertainty.
Problem 1
Draw a straight line and plot X anywhere on it.
Use your compass to trace out a circle with radius 1.5 cm. The circle intersects the line at two points. Let's make Y one of those points.
Also from point X, draw a circle of radius 2.5
This second circle will intersect another circle of radius 3.5 and this third circle is centered at point Z.
Check out the diagram below to see what I mean.
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Problem 2
Draw a straight line and plot L anywhere on it.
Adjust your compass to 4 cm in width. Draw a circle around point L.
This circle crosses the line at two spots. Focus on one of those spots and call it M.
Draw another circle centered at point M. Keep the radius at 4 cm.
The two circles intersect at two points. Focus on one of the points and call it N.
The last step is to connect L, M and N to form the equilateral triangle.
See the image below.
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Problem 3
I'm not sure how to do this using a compass and straightedge. I used GeoGebra to make the figure below instead. It's a free graphing and geometry program which is very useful. I used the same app to make the drawings for problem 1 and problem 2 earlier.
