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Y_Kistochka [10]
2 years ago
14

The sum of the areas of two squares is 818 cm2.

Mathematics
1 answer:
Elena-2011 [213]2 years ago
6 0

Answer: 17 and 23 (cm)

Step-by-step explanation:

Let c1 and c2 the side of thr squares.

\left\{\begin{array}{ccc}4*c_1+4*c_2&=&160\\c_1^2+c_2^2&=&818\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}c_1+c_2&=&40\\c_1^2+(40-c_1)^2&=&818\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}c_1+c_2&=&40\\c_1^2+-40c_1+391&=&0\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}c_1&=&23\\c_2&=&17\\\end{array}\right.\ or\ \left\{\begin{array}{ccc}c_1&=&17\\c_2&=&23\\\end{array}\right.\\

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Kitty [74]

Answer:

  160 ft²

Step-by-step explanation:

The width is 40% of the length, so is ...

  0.40 × 20 ft = 8 ft

The area is the product of length and width:

  A = LW

  A = (20 ft)(8 ft) = 160 ft²

8 0
2 years ago
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RideAnS [48]

Answer:

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Step-by-step explanation:

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BRAINLIEST!!!
Sonbull [250]

Answer:

\sqrt{37}

Step-by-step explanation:

The distance d between a point (m , n ) and a line in the form

Ax + By + C = 0 , is calculated as

d = \frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }

Here (m, n ) = (6, 2 ) and

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6x - y + 3 = 0 → A = 6, B = - 1, C = 3

d = \frac{|6(6)+-1(2)+3|}{\sqrt{6^2+(-1)^2} }

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   = \frac{37}{\sqrt{37} } × \frac{\sqrt{37} }{\sqrt{37} }

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7 0
2 years ago
If f(x) = 2x^4, then f'(3) =
valkas [14]

To find f'(3) (f prime of 3), you must find f' first.  f' is the derivative of the function f(x).

Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.

The power rule for derivatives is \frac{d}{dx} [x^{n} ] =nx^{n-1}.  In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.

f'(x) = \frac{d}{dx}(2x⁴)

f'(x) = 2(4)x³

f'(x) = 8x³

Now, to find f'(3), plug 3 into your derivative.

f'(3) = 8(3)³

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<h3>Answer:</h3>

f'(3) = 216

6 0
2 years ago
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vova2212 [387]

Answer:

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Step-by-step explanation:

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