There are two c's. You must pay attention to capitalization, there's a lowercase c and an uppercase C which represent two different variables. Also, the W is capitalized which could make your answer incorrect if you don't use the same notation.
Solving for small c..

So it's the answer shown in the picture, but it should be a capital W instead of a lowercase w.
Answer
The steel ball will be caught up in between the mercury and water medium.
Step-by-step explanation:
- Mercury with a density of 13546 kg/m^3
- water with a density of 1000 kg/m^3
- Steel with a density of 8050 kg/m^3
From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.
The steel ball will be caught in between both mixtures as the density of steel is 8050 kg/m^3.Which is more than Water but less than Mercury.
B would be the answer. hope it helps !
Since x=8y, subsitute 8y for x in other equation
y=6x-11
y=6(8y)-11
y=48y-11
minus y both sides
0=47y-11
add 11 to both sides
11=47y
divide both sides by 47

subsitute taht for y to find x
x=8y




in (x,y) form
(x,y)
Answer:
70 yd.
Step-by-step explanation:
The three streets at the intersection form a right triangle.
For a right triangle, the length of the longest side (called hypothenuse) is given by Pythagorean's theorem:

where
x is the length of the 1st side
y is the length of the 2nd side
h is the length of the hypothenuse
Here we want to find the hypothenuse.
We have:
x = 42 yd (length of the 1st side)
y = 56 yd (length of the 2nd side)
Substituting, we find h:
