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jonny [76]
3 years ago
6

Which expression can be used to determine the average rate of change in f(x) over the interval mc001-1.jpg

Mathematics
2 answers:
Mrac [35]3 years ago
8 0
The average rate of change of a function f(x) over an interval (a, b) is given by
\frac{f(b)-f(a)}{b-a}

Therefore, given a function, f(x), over an interval (2, 9), the average rate of change of the function can be found using the expression
\frac{f(9)-f(2)}{9-2}
IrinaK [193]3 years ago
8 0

Answer:

The answer is D.

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for f(x)=1/x-5 and g(x)=x^2+2 find the expression for g(x) and substitute the value of g(x) into the function in place of x to f
IRISSAK [1]

Answer:

f(x)  = (1/x) - 5

g(x) = x^2 + 2

=> f[g(x)] = [1/(x^2 +2)] - 5

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Driving to your friend's house, you travel at an average rate of 35 miles per hour. On your
Mamont248 [21]

Answer:

14 miles.

Step-by-step explanation:

Let the distance traveled from home to destination = x miles.

Speed while going to friend's house = 35 miles per hour.

Speed while coming back = 40 miles per hour.

Total Time taken for the journey = 45 minutes = 0.75 hours.

Let the time taken while going to friend's house = y hours.

Therefore, the time taken while going to friend's house = (0.75 - y) hours.

To find x and y, model the speeds of both the journeys.

Speed while going to friend's house = Distance/Time.

35 = x/y.

x = 35y (Equation 1).

Speed while coming back = Distance/Time.

40 = x/(0.75 - y).

x = 40(0.75 - y) (Equation 2).

Since x = x, therefore:

35y = 30 - 40y.

75y = 30.

y = 30/75.

y = 0.4 hours.

Put y = 0.4 hours in Equation 1:

x = 35y.

x = 35(0.4).

x = 14.

Therefore, the distance between my friend's house and my house is 14 miles!!!

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Answer:

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