<span>B) Mike does not have enough money budgeted for food or medical expenses.</span>
The average decrease in value can be solve by first solving the value at year 1 and year 2
and i think the equation is <span>f(x)=10,000(0.73)^x</span>
at x = 1
<span>f(x) = 10,000(0.73)^x
</span><span>f(1) = 10,000(0.73)^(1)
f(1) = 7300
at x = 2
</span><span>f(x) = 10,000(0.73)^x
</span><span>f(2) = 10,000(0.73)^(2)
f(2) = 5329
so the average decrease = ( 7300 - 5329) = $ 1971 per year</span><span>
</span>
Answer:
497
Step-by-step explanation:
(8 x 8 x 8) -( 9 x 2) + 3
512 - 18 + 3
Ahora que está simplificado, hay una ecuación más sencilla.
512 - 18 + 3
512 - 15 = 497
¡Espero que te ayude y que tengas un gran día!
The pile contains 12 nickels and 9 quarters.
Let <em>x</em> = the number of nickels and <em>y</em> = the number of quarters.
Then, we have two equations:
(1) $0.05x + $0.25y = $2.85
(2) x = y +3
Substitute the value of <em>x</em> from Equation (2) into Equation (1).
0.05(<em>y</em>+3) + 0.25<em>y</em> = 2.85
0.05<em>y</em> + 0.15 + 0.25<em>y</em> = 2.85
0.30<em>y</em> = 2.85 – 0.15 = 2.70
y = 2.70/0.30 = 9
Substitute the value of <em>y</em> in Equation (2).
x = 9 + 3 = 12
The pile contains 12 nickels and 9 quarters.
<em>Check</em>: 12×$0.05 + 9×$0.25 = $0.60 + $2.25 = $2.85.
