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Answer:
Following are the solution to this question:
Explanation:
Please find the complete question in the attachment.
Start of Laboratory
Dissolve 2-naphthol in the round bottom flask with ethanol.
Add pellets of sodium hydroxide and hot chips. Attach a condenser.
Heat for 20 minutes under reflux, until the put a burden dissolves.
After an additional hour, add 1-Bromobutane and reflux.
Pour the contents into a beaker with ice from a round bottom flask.
On a Bachner funnel, absorb the supernatant by vacuum filtration.
Utilizing cold water to rinse the material and dry that on the filter.
Ending of the Lab
Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.
Explanation :
Let us rewrite the given equations again.
On adding above equations, we get the following combined equation.
We have 12.1 mL of 0.033 M solution of VO₂⁺.
Let us find the moles of VO₂⁺ from this information.
From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.
Let us use this as a conversion factor to find the moles of Zn.
Let us convert the moles of Zn to grams of Zn using molar mass of Zn.
Molar mass of Zn is 65.38 g/mol.
We need 0.0392 grams of Zn metal to completely reduce vanadium.