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kati45 [8]
3 years ago
15

D c a b yfyefegyfyrgfyeerg

Chemistry
1 answer:
Colt1911 [192]3 years ago
5 0
Hshsjusidjdndbdududj and have a good day
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What are the properties of compounds, mixtures, solutions, and pure substances? please answer!
PtichkaEL [24]
Mixtures – two or more substances that are not chemically combined<span> with each other and can be </span>separated<span> by physical means. The substances in a mixture retain their individual properties. Solutions – a special kind of mixture where one substance dissolves in another.</span>
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(IMAGE) Name the following ester molecule: O O​
GuDViN [60]

Answer:

option A is correct answer

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Use the following equation to answer the questions and please show all work.
DIA [1.3K]

Answer:

a.36 g of water is produced.

b.64 g of O_{2} is consumed.

Explanation:

The reaction is 2H_{2} + O_{2}⇒2H_{2}O

a.

Given,

Weight of H_{2} reacted = 4g

Weight of 1 mole of H_{2} = 2\times1 = 2g

Therefore no. of moles of H_{2} reacted = \frac{4}{2} = 2 moles;

Also given,

Weight of O_{2} reacted = 32 g

Weight of 1 mole of O_{2} = 2\times16 = 32 g

Therefore no. of moles of O_{2} reacted = \frac{32}{32} = 1

We know that 2 moles of Hydrogen reacts with 1 mole of Oxygen to give 2 moles of water,

As we took 2 moles of Hydrogen and 1 mole of Oxygen,

Directly,from the equation we can tell 2moles of water will be produced.

Therefore no. of moles of H_{2} O produced = 2

Weight of 1 mole of water = 2\times 1+16 = 18

Therefore weight of H_{2}O produced = 2\times 18 = 36gm

b.

Given ,

72 g of H_{2}O is produced.

So,

no. of moles of H_{2}O produced =\frac{72}{18} = 4 moles

From equation For every 2 moles of water formed , 1 mole of oxygen must be required.

So for producing 4 moles of water,

No. of moles of Oxygen required = 2 moles.

Therefore weight of O_{2} reacted = 2\times32 = 64 g

Method 2:

Given,

8 g of H_{2} has reacted.

So,

no. of moles of H_{2} reacted = \frac{8}{2} = 4 moles.

From equation , we know that For every 2 moles of H_{2} reacted,1 mole of O_{2} will react.

Therefore,

No. of moles of O_{2} that reacts with 4 moles of H_{2} = 2\times1 = 2 moles

Therefore the weight of O_{2} reacted = 2\times 32 = 64 g

6 0
3 years ago
Which of the following would not cause an increase in the pressure inside a sealed container of neon gas?
r-ruslan [8.4K]

The pressure in a sealed container means the volume of container is fixed

so we cannot change the volume of container hence gas

The other factors which can affect the pressure are

a) moles of gas : if we increase the moles of gas the pressure of gas will increase

b) Temperature: if we increase the pressure of gas the pressure of gas will increase due to increase in kinetic energy

So the following cannot increase pressure

a) decrease in moles of gas

b) decrease in temperature of gas

3 0
4 years ago
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Ymorist [56]

Answer:

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Explanation:

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