Answer:
-6 and 8
Step-by-step explanation:
The standard deviation of a particular sample is equal to the standard deviation divided by the square root of the sample size. That is,
The mean of a particular sample is equal to the mean of the set the sample was taken from. That is,
Answer:
X= 8
Step by Step Explanation: Hope this helps ya darling!!
Answer:
The correct answer is:
Step-by-step explanation:
Given that:
![h(x) = f\circ g(x)= \sqrt[3]{x+3}](https://tex.z-dn.net/?f=h%28x%29%20%3D%20f%5Ccirc%20g%28x%29%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D)
![f(x) = \sqrt[3]{x+2}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%2B2%7D)
To find:
Solution:
Let 
We have
![f\circ g(x)= \sqrt[3]{x+3}\\OR\\f( g(x))= \sqrt[3]{x+3}](https://tex.z-dn.net/?f=f%5Ccirc%20g%28x%29%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D%5C%5COR%5C%5Cf%28%20g%28x%29%29%3D%20%5Csqrt%5B3%5D%7Bx%2B3%7D)
...... (1)
Now, we have let:
Putting x = in f(x), we get
![f(x) = \sqrt[3]{x+2}\\\Rightarrow f(m) = \sqrt[3]{m+2}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%2B2%7D%5C%5C%5CRightarrow%20f%28m%29%20%3D%20%5Csqrt%5B3%5D%7Bm%2B2%7D)
....... (2)
Comparing equation (1) and (2):
![\sqrt[3]{x+3} =\sqrt[3]{m+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D%20%3D%5Csqrt%5B3%5D%7Bm%2B2%7D)
Taking cubes both sides:
Hence,
The <em>correct answer </em>is:
Answer:
Last year there were 550 bison in the heard and this year it is 10% larger.
10% is also 10/100 or 0.10
To find 10% of the heard last year
550 x.0.10 = 55. To find the number in the heard this year add 550 (last year) + 55 (10% growth) = 605 or,
to find how many there are now last years heard size was 100% of the heard or 1.00. To find any percent more add it to 1.00 and multiply by the starting amount.
550 x 1.10 = 605
For the second example.
If there are 550 bison in the heard this year, and this year was a decrease of 10% from last year we can express last year's number like this.
550 = (x - (x * 0.10)) simplify;
550 = 1x - 0.10x
550 = 0.90x
Divide both sides by 0.90
x = 611.11 but it's hard to have 0.11 of a bison so realistically 611 bison last year. Subtract 10% or 61 and you indeed have 550 this year.
