Step-by-step explanation:
Area of a trapezium = SOPS/2 × ph
Sops is the sum of 4+10 = <u>1</u><u>4</u>
14/2 is 7. 7×4 = <u>2</u><u>8</u>
<u>A</u><u> </u><u>=</u><u> </u><u>2</u><u>8</u><u>c</u><u>m</u><u>²</u>
Area = L×W
10×6= 60cm²
Answer:
15.0
Step-by-step explanation:
Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.
The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)
Answer:
21
Step-by-step explanation:
14+7=21
-1/2 is what I would choose.
5=(-4)x-2. Hope this helps
