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Advocard [28]
3 years ago
5

joey made an deposit into an account that earns 6% simple interest. after 3 years joey had earned 400$. how much was joey's init

ial deposit ?
Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0
I= prt
I=$400 (0.06) (3)
I= 72
The 6% was changed into a decimal (0.06)
So I multiplied 400 x 0.06 x 3
The 400 would be the principal amount the 6% would be the rate and the 3 would be the time
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Whats the slope of the line x=-1
bonufazy [111]

Answer:

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Step-by-step explanation:

If you graph x=-1, you will get a line with x-intercept -1 and no y-intercept. If you do not have either of these things, your line does not have a constant slope.

5 0
3 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
3 years ago
Solve the system by elimination: 4x+7y=-1 8x-4z=36 6y-4z=-22
alina1380 [7]
X =5 y = -3 z= 1
Hope this helps :)
7 0
3 years ago
A tortoise challenges a hare to a four-hour race. The hare is so confident of winning that he allows the tortoise to start with
Colt1911 [192]

Count the distances that a tortoise and a hare completed.

1. Tortoise. The speed of the tortoise is constant and equal to 4 miles per hour. Then in 4 hours the tortoise completed 4·4=16 miles. It has a 10-mile lead, then the distance that the tortoise completed in total is 10+16=26 miles.

2. Hare. The speed of the hare is constant and equal to 14 miles per hour.  But the hare stops for a two-hour nap, then the hare was 4-2=2 hours running. Then the distance that hare completed is 14·2=28 miles.

3. As you can see the hare gets farther than tortoise 2 miles.

5 0
3 years ago
1. What is the solution to the system of equations?
djyliett [7]

Answer:

Step-by-step explanation:

(a) In order to use the elimination method, multiply the second equation by 2.

It becomes 2x + 4y = 20.

Subtract that from the first equation: 3x + 4y = 12

3x + 4y - 2x - 4y = 12 - 20

x = -8

Put that back in the second equation: -8 + 2y = 10

2y = 18

y = 9

(b) In order to use the substitution method, subtract 2y from the second equation.

It becomes x + 2y - 2y = 10 - 2y

x = 10 - 2y

Substitute that into the first equation:

3(10 - 2y) + 4y = 12

30 - 6y + 4y = 12

30 - 2y = 12

2y = 18

y = 9

Put back into the equation for x:

x = 10 - 2(9)

= 10 - 18

= -8

4 0
3 years ago
Read 2 more answers
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