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3 years ago

Express the following relationship as a rate. Reading 30 pages in 10 minutes

Mathematics

2 answers:

Marizza181 [45]3 years ago

6 0

Answer:

3 pages per minute

Step-by-step explanation:

If you want to find the rate of something, simply divide 30 by 10 to find out how many pages you read in that amount of time, or any other given scenario. So you would divide 30 by 3 and that would give you 3 pages per minute. :D

xxMikexx [17]3 years ago

4 0

Answer:

Step-by-step explanation:

so d=rt is the famous formula.

30= 10r

so it would be 3 pages per minute

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6 divided by 1/4 24 59 67 18 eplain how u did it

Cloud [144]

Answer:

Step-by-step explanation:

6 divided by 1/4 is the same thing as 6 multiplied by 4, so the answer is 24.

6 0

3 years ago

Read 2 more answers

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 400 babies were born, a

Masja [62]

Answer:

(a) 99% confidence interval for the percentage of girls born is [0.804 , 0.896].

(b) Yes, the proportion of girls is significantly different from 0.50.

Step-by-step explanation:

We are given that a clinical trial tests a method designed to increase the probability of conceiving a girl.

In the study 400 babies were born, and 340 of them were girls.

(a) Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of girls born = $\frac{340}{400}$ = 0.85

n = sample of babies = 400

p = population percentage of girls born

Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.85-2.58 \times {\sqrt{\frac{0.85(1-0.85)}{400} } }$ , $0.85+2.58 \times {\sqrt{\frac{0.85(1-0.85)}{400} } }$ ]

= [0.804 , 0.896]

Therefore, 99% confidence interval for the percentage of girls born is [0.804 , 0.896].

(b) Let p = population proportion of girls born.

So, Null Hypothesis, $H_0$ : p = 0.50 {means that the proportion of girls is equal to 0.50}

Alternate Hypothesis, $H_A$ : p $\neq$ 0.50 {means that the proportion of girls is significantly different from 0.50}

The test statistics that will be used here is One-sample z proportion test statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of girls born = $\frac{340}{400}$ = 0.85

n = sample of babies = 400

So, the test statistics = $\frac{0.85-0.50}{\sqrt{\frac{0.85(1-0.85)}{400} } }$

= 19.604

Now, at 0.01 significance level, the z table gives critical value of 2.3263 for right tailed test. Since our test statistics is way more than the critical value of z as 19.604 > 2.3263, so we have sufficient evidence to reject our null hypothesis due to which we reject our null hypothesis.

Therefore, we conclude that the proportion of girls is significantly different from 0.50.

8 0

3 years ago

the slide at the playground has a height of 6 feet.The base of the slide measured on the ground is 8 feet.what is the length of

NemiM [27]

The formula for finding the length is
${a}^{2} + {b}^{2} = {c}^{2}$
All we have to do is plug in the numbers.

${6}^{2} + {8}^{2} = {c}^{2}$
36 + 64 = 100

Since 100 =
${c}^{2}$
we have to find the square root.

$\sqrt{100} = 10$

The length of the slide is 10 feet.

6 0

3 years ago

Use partial products and the distributive property to calculate the product. 300 x 41.9

kolbaska11 [484]

Answer:

300*41.9=12570

6 0

3 years ago

Suppose you want to have $400,000 for retirement in 30 years. Your account earns 4% interest.

Ne4ueva [31]

Answer:

if he wants to have $400000 on gis bank in 30 years at 4 %rate then he needs to deposit $15151.5 per month

5 0

4 years ago