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2 years ago

Find the length of side AB.

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

3 0

It’s four. divide 6 by 1.5 to see how much u need to multiply one by

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A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute q in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute h in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for d, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for d in the second equation to find h, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for d and 16 for h in the third equation to find q, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago

Can you guys answer this ?

nika2105 [10]

Answer:

-7

...................

7 0

3 years ago

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Solve for px thanks

koban [17]

Px + 12 = 17
px = 5
x = 5/p

ans) D

6 0

2 years ago

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Help pleaseeee it’s due in 27 mins

Nitella [24]

Answer:

X-intercepts: (-5,0)

Y-Intercepts: (0,2)

Step-by-step explanation:

6 0

2 years ago

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An irrigation sprinkler waters

Ede4ka [16]

Answer: Use 22/7 for π. Solution: Use the formula. C = 2πr. Substitute 14 for r. C = 2π(14) Substitute 22/7 for π. C ≈ 2 x (22/7) x 14. Simplify C ≈ 2 x (22/1) x 2. C ≈ 88. So, the circumference of the region watered by the sprinkler is about 88 feet.

Step-by-step explanation: Hope this helps

8 0

1 year ago