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3 years ago

What is 975 times 65

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

3 0

The answer is 1040!

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Tell whether the lines for the pair of equations are parallel, perpendicular, or neither

attashe74 [19]

Answer:

they are parallel to each other

5 0

3 years ago

The inverse, f'(x), of f(x) =

astraxan [27]

Step-by-step explanation:

Given

$f(x) = \frac{x + 5}{x}$

$f(2) = \frac{2 + 5}{2} \\ = \frac{7}{2}$

Now

${f}^{ - 1} (x) = \frac{5}{x - 1}$

${f}^{ - 1} (2) = \frac{5}{2 - 1} \\ = \frac{5}{ 1} \\ = 5$

Hope it will help :)❤

7 0

2 years ago

.help me please thanks

Ad libitum [116K]

Its most likely c
hope it helps

7 0

3 years ago

Read 2 more answers

What is the rate of change of the line through (-8, 4) and (-10, 0)?

LenaWriter [7]

Answer: (3,8) and (-2, 10)

Step-by-step explanation:

the slope of the line passing

6 0

2 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago