What is 975 times 65

C = (F - 32) * 5/9, the letter "F" is known as which of the following?

Mice21 [21]

Answer:

F=Fahrenheit and C=Celsius

Step-by-step explanation:

7 0

3 years ago

A miniature quadcopter is located at xi = −1.75 m and yi = −5.70 m at t = 0 and moves with an average velocity having components

Black_prince [1.1K]

The quadcopter's average velocity is given in terms of change in position by

$\vec v_{\rm av}=\dfrac{\Delta x}{\Delta t}\,\vec\imath+\dfrac{\Delta y}{\Delta t}\,\vec\jmath$

where $\Delta x=x_f-x_i$ , the difference in the quadcopter's final and initial positions and $\Delta t=(1.60-0)\,\mathrm s=1.60\,\mathrm s$ .

The $x$ -component of the average velocity is 2.70 m/s, so

$2.70\dfrac{\rm m}{\rm s}=\dfrac{x_f-(-1.75\,\mathrm m)}{1.60\,\rm s}\implies \boxed{x_f=2.57\,\mathrm m}$

and the $y$ -component is -2.50 m/s, so

$-2.50\dfrac{\rm m}{\rm s}=\dfrac{y_f-(-5.70\,\mathrm m)}{1.60\,\rm s}\implies\boxed{y_f=-9.70\,\mathrm m}$

4 0

3 years ago

Show all work to factor x^4 − 5x^2 + 4 completely.

Mademuasel [1]

Answer:

(x+1) (x-1) (x+2) (x-2)

Step-by-step explanation:

Let u = x^2

= u^2 - 5u + 4

(Factor u^2 - 5u + 4)

= (u-1) (u-4)

Substitute back u = x^2

= (x^2 -1 ) (x^2 - 4)

Factor x^2 - 1 and x^2 -4

= (x+1) (x-1) (x+2) (x-2)

Hope this helped... :)

If you need to see the work for yourself, copy/paste this link

https://www.symbolab.com/solver/factor-calculator/factor%20x%5E%7B4%7D%20%E2%88%92%205x%5E%7B2%7D%20%2B%204%20

3 0

3 years ago

Read 2 more answers

the first term of an arithmetic sequence is 2 and the sum of the first 15 terms is 292.5. Find the common difference

adelina 88 [10]

Given:

First term of an arithmetic sequence is 2.

Sum of first 15 terms = 292.5

To find:

The common difference.

Solution:

We have,

First term: $a=2$

Sum of first 15 terms: $S_{15}=292.5$

The formula of sum of first n terms of an AP is

$S_n=\dfrac{n}{2}[2a+(n-1)d]$

Where, a is first term and d is common difference.

Putting $S_{15}=292.5$ , n=15 and a=2 in the above formula, we get

$292.5=\dfrac{15}{2}[2(2)+(15-1)d]$

$292.5=\dfrac{15}{2}[4+14d]$

$292.5=15[2+7d]$

Divide both sides by 15.

$\dfrac{292.5}{15}=2+7d$

$19.5=2+7d$

$19.5-2=7d$

$17.5=7d$

Dividing both sides by 7, we get

$\dfrac{17.5}{7}=d$

$2.5=d$

Therefore, the common difference is 2.5.

8 0

3 years ago

If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the

denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

Solution:

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

$\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)$

Now at head wind → $720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)$

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0

3 years ago