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motikmotik
3 years ago
7

Choose correct way to rewrite 56% as a decimal number.

Mathematics
2 answers:
disa [49]3 years ago
5 0
You would write 56% as 0.56.
denis-greek [22]3 years ago
5 0

<u>Answer</u>:

 The correct answer is:  [B]:  " 0.56 " .

<u>Step-by-step explanation</u>:

<u>Note</u>:

 " 56%   = " (\frac{56}{100}) " ;

              =  (56) ÷ (100)  =  0.56  ;  

  →  which corresponds to:  " Answer choice:  [B]: " 0.56 " .

______________________________________________

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RideAnS [48]
3 meters below sea level represents a -3
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4 0
3 years ago
Show that: (3x-1)(x+5)(4x-3) = 12x^3 + 47x^2 - 62x +15 for all values of x. (3x-1)(x+5)(4x-3) = (?????)(4x-3) Expand into 6 term
lara31 [8.8K]
<span>(3x - 1)( x + 5)(4x - 3) = 12x^3 + 47x^2 - 62x +15 </span>
<span>(3x^2 – x + 15x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>(3x^2 + 14x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
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<span>12x^3 – 47x^2 - 62x + 15 = <span>12x^3 + 47x^2 - 62x +15 </span></span>

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8 0
3 years ago
Read 2 more answers
Given 6(x) = (x+41, what is b(-10)?
prisoha [69]

The value of b(-10) is 31

Explanation:

The given expression is b(x)=x+41

We need to determine the value of b(-10)

The value of b(-10) can be determined by substituting x=-10 in the expression b(x)=x+41

Thus, we have,

b(-10)=-10+41

Adding the terms, we have,

b(-10)=31

Thus, the value is 31.

Therefore, the simplified value of the expression by substituting x=-10 in the expression b(x)=x+41 is 31.

7 0
3 years ago
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5 0
3 years ago
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2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?
mezya [45]

Answer:

the inverse of the quadratic function f(x) = x^2 - 3  is \mathbf{f^{-1}(x)=\pm \sqrt{x+3}}

Step-by-step explanation:

We need to find inverse of the quadratic function f(x) = x^2 - 3

Let

y=x^2-3

Replace x and y

x=y^2-3

Now, we will solve for y

Adding 3 on both sides

x+3=y^2-3+3

x+3=y^2

Taking square root on both sides

\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}

Now replace y with f^{-1}(x)

f^{-1}(x)=\pm \sqrt{x+3}

So, the inverse of the quadratic function f(x) = x^2 - 3  is \mathbf{f^{-1}(x)=\pm \sqrt{x+3}}

3 0
3 years ago
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