Answer:
(A) - (5)
(B) - (4)
(C) - (1)
(D) - (2)
Step-by-step explanation:
(A) We are given the polynomial (x+4)(x−4)[x−(2−i)][x−(2+i)]
(5) The related polynomial equation has a total of four roots; two roots are complex and two roots are real.
(B) We are given the polynomial (x+i)(x−i)(x−2)³(x−4).
(4) The related polynomial equation has a total of six roots; two roots are complex and one of the remaining real roots has a multiplicity of 3.
(C) We are given the polynomial (x+3)(x−5)(x+2)²
(1) The related polynomial equation has a total of four roots; all four roots are real and one root has a multiplicity of 2.
(D) We are given the polynomial (x+2)²(x+1)²
(2) The related polynomial equation has a total four roots; all four roots are real and two roots have a multiplicity of 2. (Answer)
There are a total of 16 200 units with a total costs of 37 585.60 dollars. Now, Given with the choices for the answer, let's find out which one is correct. To be able to get the answer, simply divide the total costs, with the total number of units. => 37 585.60 dollars / 16 200 units => 2.3201 dollars per unit.Next, we need to round this cents to the nearest given options.Since the number next to hundredths is less than 5 , the let's round it to : => 2.32. - this is the correct answer.<span>
</span>
Answer:
slope is undefined
Step-by-step explanation:
Answer:
C) senior citizen ticket 10$, child ticket 11$
Step-by-step explanation:
Answer:
The mean and standard deviation of Y is $6.56 and $2.77 respectively.
Step-by-step explanation:
Consider the provided information.
Let Y represent their profit on a randomly selected pizza with this promotion.
The company is going to run a promotion where customers get $2 off any size pizza.
Therefore, 

So the mean will be reduced by 2.



If we add or subtract any constant number from a given distribution, then the mean is changed by the same number(i.e constant number) but the standard deviation will remain the same.
Therefore 
Hence, the mean and standard deviation of Y is $6.56 and $2.77 respectively.