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3 years ago

10

Devont had a handful of dimes and quarters in his pocket. He counted 41 coins and realized they were worth $7.55. Write and solv

e a system of linear equations to determine the number of dimes and quarters Devont had.

1 answer:

MatroZZZ [7]3 years ago

6 0

Answer:D:18 Q:23

Step-by-step explanation:

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Help Q-Q 7/10c =4 1/5

shepuryov [24]

$\huge\mathfrak\green{answer}$

$= q - \frac{q7}{10} c = \frac{41}{5}$

$\red{multiply}$

$= q - \frac{cq7}{10} = \frac{41}{5}$

$\red{subtract \: q \: from \: both \: sides}$

$= q - \frac{cq7}{10} - q = \frac{41}{5} - q$

$\red{now \: simplify}$

$= - \frac{cq7}{10} = \frac{41}{5} - q$

$\red{multiply \: 10 \: both \: sides}$

$= 10( - \frac{cq7}{10} ) = 10. \frac{41}{5} - 10q$

$\red{simplify}$

$= - cq7 = 82 - 10q$

$\red{now \: divide}$

$= \frac{ - cq7}{ - q7} - \frac{82}{ - q7} - \frac{10q}{ - q7}$

$\red{simplify}$

$= c = - \frac{82 - 10q}{q7} (q≠0)$

Brainliest? :) (I'd really appreciate if you mark me as brainliest)

$\huge\mathfrak\green{thank \: you}$

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