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2 years ago

What is the greatest common multiple of 9 and 27

Mathematics

1 answer:

dusya [7]2 years ago

6 0

Hi,

The greatest common multiple of 9 and 27 is 9

explanations:

9 x 1 = 9

9 x 3 = 27

✅;-)

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Simplify -27z^5 +(-26z^5)

Oksana_A [137]

Answer:

-53z^5

Step-by-step explanation:

8 0

3 years ago

Campbell’s paycheck was $257.29. She put 1/4 of her paycheck into a savings account and used 1/3 of what was left to pay bills.

Stells [14]

Answer:

She has $128.65 left

Step-by-step explanation:

$257.29 x 1/4 = $64.32

$257.29 - $64.32 = $192.97

$192.97 x 1/3 = $64.32

$192.97 - $64.32 = $128.65

BRAINLIEST PLEASEEE

4 0

2 years ago

Read 2 more answers

Help pls 2,4 +0,8=........+1,21=........+1,78=........-5,14=

Mrrafil [7]

Lets write this out:-

2.4 + 0.8 = ________ + 1.21 = ______ + 1.78 = ______ - 5.14 = _____

So to solve d blanks we will do d following:-

2.4 + 0.8 = 3.2

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 + 1.21 = ______ + 1.78 = ______ - 5.14 = ____

Now lets solve again:-

3.2 + 1.21 = 4.41

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 + 1.21 = 4.41 + 1.78 = ______ - 5.14 = ____

Now lets solve again:-

4.41 + 1.78 = 6.19

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 + 1.21 = 4.41 + 1.78 = 6.19 - 5.14 = ____

Now lets solve again:-

6.19 - 5.14 = 1.05

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 + 1.21 = 4.41 + 1.78 = 6.19 - 5.14 = 1.05

So, 2.4 + 0.8 = 3.2 + 1.21 = 4.41 + 1.78 = 6.19 - 5.14 = 1.05

Hope I helped ya!! xD

7 0

3 years ago

PLEASE HELP BEFORE MIDNIGHT 2/14/22

spayn [35]

The answer is 1 and 5

3 0

2 years ago

What's the next number? 0 , 1/3 , 1/2 , 3/5 , 2/3

madam [21]

Answer:

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 is 5/7

Step-by-step explanation:

The given numbers are;

0, 1/3, 1/2, 3/5, and 2/3

The number sequence is formed adding $\dfrac{1}{\left (\dfrac{n^2 + n}{2} \right ) }$ to each (n - 1)th term to get the nth term number in the sequence, with the first term equal to 0, as follows;

For the 2nd term, the (n - 1)th term is 0, and n = 2, gives;

The

$0 +\dfrac{1}{\left (\dfrac{2^2 + 2}{2} \right ) } = 0 + \dfrac{1}{3} = \dfrac{1}{3}$

For the 3rd term, the (n - 1)th term is 1/3, and n = 3, gives;

$\dfrac{1}{3} +\dfrac{1}{\left (\dfrac{3^2 + 3}{2} \right ) } = \dfrac{1}{3} + \dfrac{1}{6} = \dfrac{1}{2}$

For the 4th term, the (n - 1)th term is 1/2, and n = 4, gives;

$\dfrac{1}{2} +\dfrac{1}{\left (\dfrac{4^2 + 4}{2} \right ) } = \dfrac{1}{2} + \dfrac{1}{10} = \dfrac{3}{5}$

For the 5th term, the (n - 1)th term is 3/5, and n = 5, gives;

$\dfrac{3}{5} +\dfrac{1}{\left (\dfrac{5^2 + 5}{2} \right ) } = \dfrac{3}{5} + \dfrac{1}{15} = \dfrac{2}{3}$

For the next or 6th term, the (n - 1)th term is 2/3, and n = 6, gives;

$\dfrac{2}{3} +\dfrac{1}{\left (\dfrac{6^2 + 6}{2} \right ) } = \dfrac{2}{3} + \dfrac{1}{21} = \dfrac{15}{21} = \dfrac{5}{7}$

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 = 5/7.

6 0

3 years ago