Answer:
3) 0.30
The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given 'A' plays a sport
B work part time
Given P(A) = 0.48
P(B) = 0.40
P(A∩B) =0.12
P(A∪B)¹ =0.24
<u><em>Step(ii)</em></u>:-
By using conditional probability
and similarly
The probability a randomly selected<em> student plays a sport</em> given they work part time
Now
<u>Final answer</u>:-
The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30
The point of intersection of the two lines is at (1,-1)
<h3>System of equation</h3>
The given system of expression is shown below
x - 2y = 3
5x + 3y = 2
The solution to the system of equation is the point of intersection
From equation 1
x = 3 + 2y
Substitute into 2
5(3+2y) + 3y = 2
15 +10y + 3y = 2
13y = -13
y = -1
Substitute y = -1 into 3
x = 3 + 2y
x = 3+(-2)
x = 1
Hence the point of intersection of the two lines is at (1,-1)
Learn more on system of equation here: brainly.com/question/25976025
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