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3 years ago

The perimeter of a rectangle is 152m. If the length is one morethan twice of its width. Find the length and width of rectangle.

Mathematics

1 answer:

sergejj [24]3 years ago

3 0

Step-by-step explanation:

Perimeter of a Rect.= 2(l+b)

b= x

l= 2x

Equation

152= 2(2x+x)

152= 2(3x)

152= 6x

x= 25.33

2x= 50.66

Therefore length is 50.66m and breadth is 25.33m

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Show your work, simple translations. Will give 5 star, brainliest, and a like on your answer.

fgiga [73]

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2 years ago

If the diameter is 21m what is the radius? if the radius is 3.25mm what is diameter?

RoseWind [281]

Answer:

(a)

radius=diameter/2

=21/2=10.5m

(b)

radius=diameter/2

=3.25/2=1.625mm

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3 years ago

In the statement, “Weight is a function of height,” which variable is the input and which is the output?

3241004551 [841]

Answer:

A. Height is input, Weight is output

Step-by-step explanation:

We are given the statement,

"Weight is a function of height".

As we know,

In a function of the form $y=f(x)$ , the input variable is 'x' and the output variable is 'y'.

If we write the given statement in the form $y=f(x)$ , we get,

$Weight=f(Height)$

This means that the input variable is 'Height' and the output variable is 'Weight'.

Hence, option A is correct.

5 0

3 years ago

Which equation is an identity?

kirza4 [7]

Answer:

Option (3).

Step-by-step explanation:

Option (1).

3(x - 1) = x + 2(x + 1) + 1

3x - 3 = x + 2x + 2 + 1

3x - 3 = 3x + 3 [Not True]

Therefore, this equation is not an identity.

Option (2).

x - 4(x + 1) = -3(x + 1) + 1

x - 4x - 4 = -3x - 3 + 1

-3x - 4 = -3x - 2 [Not true]

Therefore, this equation is not an identity.

Option (3).

2x + 3 = $\frac{1}{2}(4x + 2) + 2$

2x + 3 = 2x + 1 + 2

2x + 3 = 2x + 3 [True]

Therefore, this equation is an identity.

Option (4).

$\frac{1}{2}(6x-3)=3(x+1)-x-2$

3x - 1.5 = 3x + 3 - x - 2

3x - 1.5 = 2x + 1 [Not true]

Therefore, this equation is not an identity.

6 0

3 years ago

Read 2 more answers

During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for

AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is : $\hat p$ = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.345

n = sample of participants = 3532

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p= [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ , $0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ ]

= [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

6 0

3 years ago

The perimeter of a rectangle is 152m. If the length is one morethan twice of its width. Find the length and width of rectangle.​

The perimeter of a rectangle is 152m. If the length is one morethan twice of its width. Find the length and width of rectangle.