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Katen [24]
3 years ago
10

Calculate the mass of 3 moles of CCI4

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

So one mole of ccl4 contains 152 grams. it implies that 3 moles of ccl4 contains 152 * 3 grams. it is equal to 456. grams.

Explanation:

Hope this helps

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The elementary reaction 2H20(g)<--->2H2(g)+O2(g) proceeds at a certain temperature until the partial pressures of H2O, H2,
olya-2409 [2.1K]

Answer:

4.9 x 10⁻⁶.

Explanation:

  • For the reaction:

<em>2H₂O(g) ⇄ 2H₂(g) + O₂(g),</em>

'

P of H₂ = 0.002 atm, P of O₂ = 0.006 atm, and P of H₂O = 0.07 atm.

∴ The equilibrium constant (Kp) = (P of H₂)²(P of O₂)/(P of H₂O)² = (0.002 atm)²(0.006 atm)/(0.07 atm)² = 4.9 x 10⁻⁶.

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Is the element CH4 a metal or non metal
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What is the ph of a solution of 0.50 m acetic acid?
frosja888 [35]
You need to use the Ka for the acetic acid and the equilibrium equation.

Ka = 1.85 * 10^ -5

Equilibrium reaction: CH3COOH (aq) ---> CH3COO(-) + H(+)

Ka = [CH3COO-][H+] / [CH3COOH]

Molar concentrations at equilibrium

CH3COOH         CH3COO-     H+

 0.50  - x                  x                 x

Ka = x*x / (0.50 - x) = x^2 / (0.50 - x)

Given that Ka is << 1 => 0.50 >> x and 0.50 - x ≈ 0.50

=> Ka ≈ x^2 / 0.50

=> x^2 ≈ 0.50 * Ka = 0.50 * 1.85 * 10^ -5 = 0.925 * 10^ - 5 = 9.25 * 10 ^ - 6

=> x = √ [9.25 * 10^ -6] = 3.04 * 10^ -3 ≈ 0.0030

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Answer: 2.5
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