photosynthesis: the process when plants make their own food using sunlight
The volume occupied by 0.102 mole of the helium gas is 2.69 L
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Number of mole (n) = 0.102 moles
- Pressure (P) = 0.95 atm
- Temperature (T) = 305 K
- Gas constant (R) = 0.0821 atm.L/Kmol
- Volume (V) =?
<h3>How to determine the volume </h3>
The volume of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both sides by P
V = nRT / P
V = (0.102 × 0.0821 × 305) / 0.95
V = 2.69 L
Thus, the volume of the gas is 2.69 L
Learn more about ideal gas equation:
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Answer:
Explanation:
The stoichiometry for this reaction is
The rate for this reaction can be written as
![-r_{NO_2}=-\frac{d\left[NO_2\right]}{dt}=\frac{(0.01-0.008)M}{100s}=2\times{10}^{-5}\frac{M}{s}](https://tex.z-dn.net/?f=-r_%7BNO_2%7D%3D-%5Cfrac%7Bd%5Cleft%5BNO_2%5Cright%5D%7D%7Bdt%7D%3D%5Cfrac%7B%280.01-0.008%29M%7D%7B100s%7D%3D2%5Ctimes%7B10%7D%5E%7B-5%7D%5Cfrac%7BM%7D%7Bs%7D)
This rate of disappearence of 
can be realated to the rate of appearence of 
as follows (the coefficients of each compound are defined by the stoichiometry of the reaction)
