11 - Lulu the Lioness: A Heroine's Story
1 answer:
You might be interested in
If we name the gene for hands and fingers with A, the possible genotypes are Aa and AA for malformed hands with shortened fingers and aa for normal hands and fingers.
If we name the gene for hair with B, the possible genotypes are Bb and BB for woolly hair and bb for normal hair.
A woman with normal hands and non-woolly hair has a genotype aabb while her husband who has malformed hands and woolly hair might have AaBb, AaBB, AABb or AABB genotypes.
Since their first child has normal hands and non-woolly hair:aabb we can conclude that he inherited half of recessive alleles from mother, and other half from father. That means that father in his genotype contain both recessive alleles: AaBb
P: aabb x AaBb
F1: (table)
4/16 or ¼ is the possibility that one child will be with normal hands and woolly hair and ¼* 1/4 is the possibility that both of them will be with normal hands and woolly hair
