The answer to this question is a protocol.
The following cose will be used to copy assignment operator for CarCounter
<u>Explanation:</u>
Complete Program:
#include <iostream>
using namespace std;
class CarCounter
{
public:
CarCounter();
CarCounter& operator=(const CarCounter& objToCopy);
void SetCarCount(const int setVal)
{
carCount = setVal;
}
int GetCarCount() const
{
return carCount;
}
private:
int carCount;
};
CarCounter::CarCounter()
{
carCount = 0;
return;
}
// FIXME write copy assignment operator
/* Your solution goes here */
CarCounter& CarCounter::operator=(const CarCounter& objToCopy)
{
if(this != &objToCopy)
carCount = objToCopy.carCount;
return *this;
}
int main()
{
CarCounter frontParkingLot;
CarCounter backParkingLot;
frontParkingLot.SetCarCount(12);
backParkingLot = frontParkingLot;
cout << "Cars counted: " << backParkingLot.GetCarCount();
cout << endl << endl;
system("pause");
return 0;
}
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The for-loop given in the question is:
for ( j = 0; j < 10; j++ )
{
appendItem (myList, aNumber); //this loop append a number to a list myList
}
This loop starts from J variable's value zero and when J's value is less than 10, the loop iterate through its body until J's value becomes greater or equal to 10. As J's value exceed nine, the loop will get terminated.
So this loop repeats 10 times its loop body, at the 11th time, the condition becomes false and the loop will get terminated.
Answer:
I need help I don't get a this questions please asap?
Explanation: Head-on collisions. Some simple solutions can help to reduce the risk of head-on crashes. ...
Run-off road crashes. This is when a vehicle collides with a stationary object, such as a sign or lamppost, after leaving the road. ...
Intersection crashes. ...
Vulnerable road users. ...
Much work to be done.
Aug 31, 2018
