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EleoNora [17]
3 years ago
10

8r - 4 (7r - 5) this is the question im struggling with​

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

i am pretty sure the answer is:

= -20r + 20

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Expand and simplify this equation plz, 4(3x+5) - 5(8x+2)
omeli [17]

4(3x + 5) - 5(8x + 2) \\ 12x + 20 - 40x - 10 \\ 12 x - 40x + 20 - 10 \\  - 28x + 10

7 0
2 years ago
SOMEONE HELP ME WITH THIS
Alexandra [31]

Answer:

X=7 and y=6

Step-by-step explanation:

Y=-2x + 20.......eq(i)

6x-5y=12.....eq(ii)

Now, putting y= - 2x +20 in eq (ii)

6x - 5(-2x + 20)=12

6x + 10x - 100 = 12

16x=12+100

X=112 /16

X=7

Then, putting x=7 in eq (i)

Y=-2*7 +20

=-14 +20

=6

8 0
3 years ago
Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.
likoan [24]

Let v be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}

where s_A,\ s_B are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if s_A=s_B, and we know that this happens after two hours, i.e. at t=2

\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450

Solving this equation for v we have

2v = -\dfrac{16}{7}v+450 \iff \dfrac{30}{7}v=450 \iff v=\dfrac{450\cdot 7}{30} = 105

So, train A is travelling at 105 km/h. This implies that train B travels at

105\cdot \dfrac{8}{7} = 15\cdot 8=120 \text{ km/h}

5 0
3 years ago
Solve for s.<br><br> s<br> 3<br> = 2
tresset_1 [31]

S= 5? that's at the top of my head

5 0
3 years ago
Read 2 more answers
paul was given 2760$ to buy toys for a group of children.A)what would be the greatest number of toys paul could buy if each toy
Radda [10]

Answer:

2760 ÷ 9 = x

x = 306

306(9) = 2754

2760 - 2754 = 6

Have a good day! :)

7 0
2 years ago
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