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3 years ago

Describe the relationship between n and 4 that will make the value of the expression 7×n/4 great her than 7

1 answer:

5 0

If you want an answer greater that 7, your fraction needs to be greater than 1.
n can be any number greater than 4

$7 \times \frac{4}{4} = 7$
$7 \times \frac{8}{4} = 14$

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Please Help!!!

DochEvi [55]

Sally earns per hour = $12

Sally works for in a week = 16 hours.

So, Sally earns in a week = $12\times16=192$

Sally can save money each week= 20% of 192

$\frac{20}{100}\times192=38.40$

A. How much does she earn each week ? Sally earns $192 in a week.

B. How much money will she save each week? Sally will save $38.40 each week.

C. How much money will she save each month (assume there are 4.3 weeks in a month)

Savings of 1 week = $ 38.40

Savings of 4.3 weeks = $4.3\times38.40=165.12$

Hence, she will save $165.12 in a month.

D. How many months will it take her to save the money?

Total money needed = $1800

Number of months needed to collect this amount =

$\frac{1800}{165.12}=10.90$

Hence, it will take 11 months approx to save $1800.

5 0

3 years ago

Which statement is not true about the pattern shown?<br> 2 4 8 16<br> 3: 612' 24'

hram777 [196]

Answer:

Each fraction is greater than the previous fraction.

Explanation:

The bigger the denominator, the smaller the fraction.

8 0

3 years ago

Read 2 more answers

Please answer all three questions Pleaseeeeee tysmm <3

oee [108]

Answer: 2 3/4 > 2.68 is correct (only)

Step-by-step explanation: 2 3/4 = 2.75, and 2.75 is greater than 2.68

The rest are incorrect. 7.895 * 10^2 (100) = 789.5, and 5.43 * 10^3 (1000) = 5430. So 789.5 > 5430 is false.

Sqrt(63) = 7.93, and 7.93 > 8.11 is false.

Absolute values ( | | ) mean that no matter if it is negative or positive, it will become positive (unless the negative sign is outside the absolute value). 1.5 > 3.2 is false, and even without the absolute value, -1.5 is still less than 3.2

6 0

2 years ago

What is the x-coordinate of point P on the coordinate grid?

grin007 [14]

Answer:

-3/2

Step-by-step explanation:

We have to see where the point lies, check the x-axis from the graph.

(-3/2, 1/2)

x = -3/2

5 0

3 years ago

Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand

dybincka [34]

Answer: Part a) $P(a)=\frac{1}{\binom{r+w}{r}}$

part b) $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}$

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = $P(E)=\frac{Favourablecases}{TotalCases}$

For part a)

Probability that a red ball is drawn in first attempt = $P(E_{1})=\frac{r}{r+w}$

Probability that a red ball is drawn in second attempt= $P(E_{2})=\frac{r-1}{r+w-1}$

Probability that a red ball is drawn in third attempt = $P(E_{3})=\frac{r-2}{r+w-1}$

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = $P(E_{i})=\frac{r-i}{r+w-i}$

Thus the probability that events $E_{1},E_{2}....E_{i}$ occur in succession is

$P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...$

Thus $P(E)$ = $\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!$

Thus our probability becomes

$P(E)=\frac{1}{\binom{r+w}{r}}$

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at $(r+1)^{th}$ draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals $\binom{r}{r-1}$

Thus the probability becomes $P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}$

Thus required probability of case b becomes $P(E)+ P(E_{i})$

= $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\$

7 0

3 years ago