7/16 + 3/8 + Blank = 1
7/16 + 6/16 + 3/16 = 1
convert 3/8 to 6/16 then add 7+6 which = 13
that would be 13/16 then figure out that 13+3 =16 so 13/16+3/16= 16/16 or 1
Answer:
what is expected at 7am is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.
Step-by-step explanation:
In this question, we are asked to calculate if the prediction made by an equation modeled is correct.
Firstly let’s look at the equation in question;
y = 3t - 6
where y is the snow depth and t is the number of hours after midnight.
now we are looking at 7am, that’s 7 hours past 12am, meaning 7 hours after midnight.
let’s plug the value of t as 7 into the equation
y = 3(7) - 6
y = 21-6
y = 15 inches
according to the equation by Kevin, what is expected is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.
Lets write the problem info into an equation and solve step by step:
7(1/3 + 4/5)
the minimum common multiple of 3 and 5 is 15, so we multiply and divide the fractions by a proper number to convert them to be divided by 15 so is easier to add them:
<span>(1/3)(5/5) = (1*5)/(3*5) = 5/15
(4/5)(3/3) = (4*3)/(5*3) = 12/15
</span>so we substitute in the original equation:
7(1/3 + 4/5<span>)
</span>= 7(5/15 + 12/15<span>)
= 7(17/15)
= (7*17)/15
= 119/15</span>
Answer:
69.08
Step-by-step explanation:
π×d
3.14×22=69.08
Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } 
This area is equal to 125 as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒ 
- 18 a +80 -125 =0
⇒ - 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a 
4.
Thus the required answer is 15 cm.
