Which of the following is a quadratic function?

1. En una biblioteca quieren comprar una computadora que

miss Akunina [59]

Answer:

678.74

that might be the question since I don't really understand what it says really

8 0

3 years ago

(a) What is a sequence? A sequence is an unordered list of numbers. A sequence is the sum of an ordered list of numbers. A seque

crimeas [40]

Step-by-step explanation:

A sequence is an ordered list of numbers.

lim n → ∞ an = 8 means that as n approaches infinity (becomes large), an approaches 8.

lim n → ∞ an = ∞ means that as n approaches infinity (becomes large), an approaches infinity (becomes large).

6 0

3 years ago

Find the area .............

Natali5045456 [20]

Answer:

Area of the Trapezoid is= $13.5cm^2$

Step-by-step explanation:

The given figure is in the shape of a trapezoid:

Area of a trapezoid= (1/2)*(Sum of parallel opposite sides)* (Distance between the parallel sides)

The parallel sides are: 6 cm and 3 cm

Distance between parallel sides= 3 cm

Area:

$=\frac{1}{2} *(6+3)*3\\\\=\frac{1}{2}*9*3\\\\=\frac{27}{2} \\\\=13.5 cm^2$

Area of the Trapezoid is= $13.5cm^2$

5 0

3 years ago

Find the values of k so that each remainder is three. 10. (x^2+ 5x + 7) = (x + k)

Goryan [66]

Answer:

$k=1\text{ or } k=4$

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. It states that if we divide a polynomial P(x) by a binomial in the form (x - a), then our remainder will be P(a).

We are dividing:

$(x^2+5x+7)\div(x+k)$

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

$(-k)^2+5(-k)+7=3$

Simplify:

$k^2-5k+7=3$

Solve for k. Subtract 3 from both sides:

$k^2-5k+4=0$

Factor:

$(k-1)(k-4)=0$

Zero Product Property:

$k-1=0\text{ or } k-4=0$

Solve:

$k=1\text{ or } k=4$

So, either of the two expressions:

$(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)$

Will yield 3 as the remainder.

5 0

3 years ago

A basketball gymnasium is 25 meters high, 80 meters wide and 200 meters long. We want to connect two strings, one from each of t

Rudiy27

Answer:

a) the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be 216.85 m

c) the angle that is formed by the strings is 1.23 rad

Step-by-step explanation:

assuming that we stand on one of the corners on the floor , so our coordinates are (0,0,0) , then the coordinates of the center of the gymnasium are found through

x center = (25 + 0)/2 = 12.5 m

y center = (80+ 0)/2 = 40 m

z center = (200+ 0)/2 = 100 m

then the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be the modulus of the vector that points from our position to the diagonally opposite corners

|S| = √(25²+80²+200²) = 216.85 m

c) the angle can be found through the dot product of the vectors that represent the strings S₁ and S₂

S₁ =(25,80,10)

S₂ =(-25,80,100)

then

S₁*S₂ = 25*(-25) +80*80 + 100*100 = 15775

but also

S₁*S₂ = |S₁||S₂| cos θ = |S|² * cos θ

S₁*S₂ = |S|² * cos θ

cos θ= S₁*S₂/|S|²

θ= cos ⁻¹ ( S₁*S₂/|S|² ) = cos ⁻¹ [15775/(25²+80²+200²)] = 1.23 rad

7 0

3 years ago