Let's assume
number of birds with 2 wings is x
number of birds with 4 wings is y
A nature museum has 2008 specimens of early birds
so,
![x+y=2008](https://tex.z-dn.net/?f=x%2By%3D2008)
Total of wings of 2 wings bird =2x
Total of wings of 4 wings bird =4y
The specimens have a total of 4384 wings
so, we get
![2x+4y=4384](https://tex.z-dn.net/?f=2x%2B4y%3D4384)
we can divide both sides by 2
![x+2y=2192](https://tex.z-dn.net/?f=x%2B2y%3D2192)
so, we get system of equations as
![x+y=2008](https://tex.z-dn.net/?f=x%2By%3D2008)
![x+2y=2192](https://tex.z-dn.net/?f=x%2B2y%3D2192)
we can solve for x and y
We can subtract both equations
![2008-y+2y=2192](https://tex.z-dn.net/?f=2008-y%2B2y%3D2192)
![y=184](https://tex.z-dn.net/?f=y%3D184)
![x=2008-184](https://tex.z-dn.net/?f=x%3D2008-184)
![x=1824](https://tex.z-dn.net/?f=x%3D1824)
![y=184,\:x=1824](https://tex.z-dn.net/?f=y%3D184%2C%5C%3Ax%3D1824)
so,
number of birds with 2 wings is 1824
number of birds with 4 wings is 184.............Answer
Answer:
Acute angle
Step-by-step explanation:
Given that m<C =
, to find out the type of angle angle C is, evaluate the expression given by substituting x = 13, in the expression.
m<C = ![\frac{11x + 85}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B11x%20%2B%2085%7D%7B3%7D%20)
m<C = ![\frac{11(13) + 85}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%2813%29%20%2B%2085%7D%7B3%7D%20)
m<C = ![\frac{228}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B228%7D%7B3%7D%20)
m<C = 76°
Acute angles are less than 90°.
m<C is less than 90°, therefore it is an acute angle.
100 to 49. Because area is units squared, and it is finding by multiplying the side lengths, you would simply square the ratio.
Answer:
TanФ=-1.793
Step-by-step explanation:
![Sin^{2} (A) + Cos^{2} (A) = 1](https://tex.z-dn.net/?f=Sin%5E%7B2%7D%20%28A%29%20%2B%20Cos%5E%7B2%7D%20%28A%29%20%3D%201)
![Sin(A)=\sqrt{1-Cos^{2} (A)}](https://tex.z-dn.net/?f=Sin%28A%29%3D%5Csqrt%7B1-Cos%5E%7B2%7D%20%28A%29%7D)
![Tan(A) = \frac{Sin(A)}{Cos(A)}](https://tex.z-dn.net/?f=Tan%28A%29%20%3D%20%5Cfrac%7BSin%28A%29%7D%7BCos%28A%29%7D)
![Tan(A) =\frac{\sqrt{1-Cos^{2}(A) } }{Cos(A)} \\Tan(A) =\frac{\sqrt{1-(-.487)^{2} } }{-.487}=-1.793433202](https://tex.z-dn.net/?f=Tan%28A%29%20%3D%5Cfrac%7B%5Csqrt%7B1-Cos%5E%7B2%7D%28A%29%20%7D%20%7D%7BCos%28A%29%7D%20%5C%5CTan%28A%29%20%3D%5Cfrac%7B%5Csqrt%7B1-%28-.487%29%5E%7B2%7D%20%7D%20%7D%7B-.487%7D%3D-1.793433202)
Answer:
6 groups
2 girls, 3 boys
Step-by-step explanation:
To find the answer, first find the Greatest Common Factor or the GCF. The GCF in this case is 6. So, the amount of groups is 6. Then divide each number by 6, so there will be 2 girls in each group and 3 boys in each group.