= 14,154.81 / 120 = $117.96
= 14,154.81 / 44,154.81 = 32.1%
<u>Answer:</u>
P (S∩LC) = 0.03
<u>Step-by-step explanation:</u>
We are given that the probability that someone is a smoker is P(S)=0.19 and the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158.
Given the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).
P (LC|S) = P (S∩LC) / P (S)
Substituting the given values to get:
0.158 = P(S∩LC) / 0.19
P (S∩LC) = 0.158 × 0.19 = 0.03
Let 'x' represent the amount of 50% mixture used, then '20-x' represents the amount of 10% mixture used
0.25(20) = 0.50x + 0.10(20-x)
solving for 'x' we have x=7.5
20-7.5 = 12.5
7.5 pounds of 50% mixture should be combined with 12.5 pounds of 10% mixture
Answer:
1,177.5cm^3 of candle wax will be required.
Step-by-step explanation:
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