<span>These are five questions and five answers.
Part 1.] Identify the following series as arithmetic, geometric, both, or neither. Includes picture
Answer: arithmetic
Justification:
The arithmetic series are those in which the distance (difference) between any consecutive terms is constant, so you can find the term An adding the difference to the previous term, A(n-1).
In this case the series is:
∞
∑ (3 + na) =>
n=1
Term1: 3 + a
Term2: 3 + 2a
Term3: 3 + 3a
Term3: 3 + 4a
As you see, the difference between two consecutive terms is a, which shows that it is an arithmetic series.
Part 2.] Evaluate C(3, 3)
A.] 1
B.] 6
C.] 24<span>
Answer: option A) 1.
Explanation:
The formula for combinations is Cm,n = m! / [n! (m - n)! ]
So, for C3,3, C3,3 = 3! / [3! 0!] = 3! / 3! = 1.
From this you might learn that Cm,m for any m is always 1.
Part 3.] Evaluate C(6,3)
A.] 20
B.] 120
C.] 720
Answer: option A) 20
Explanation:
Use the same formula, Cm,n = m! / [n! (m - n)! ]
C6,3 = 6! / [3! 3! ] = 6*5*4 / (3*2*1) = 5*4 = 20
Part 4.] </span>How many subsets of four elements each exist in a set of seven elements?
A.] 4!
B.] C(7, 4)
C.] P(7, 4)
Answer: option B) C(7,4)
Explanation
You have to select collections of 4 elements from a set of 7 elements, and must realize that the order is irrelevant, i.e. it is the same the set ABCD as the set ACBD or DCAB or any combination of those four elements. So, the answer is a combination and not a permutation.
The number of subsets of 4 elements that you can form with 7 elements is: C(7,4), which is the option B.
Part 5.] What is the probability of having 3 children that are all boys?
A.] 1/2
B.] 1/8
C.] 3/8
Answer: option B: 1/8
Explanation:
The number of possible outcomes is 2 * 2 * 2 = 8
Only one of those outcomes is for all boys = 1
Therefore the probability is 1/8
You can see that representing the possible outcomes using B for boys and G for girls:
1) BBB (three boys)
2) BBG
3) BGB
4) BGG
5) GBB
6) GBG
7) GGB
8) GGG
Those are the 8 possible outcomes and as seen only one is for 3 boys.
</span>
(-9,-2) (1,3)
slope = (3 - (-2) / (1 - (-9) = 5/10 = 1/2
y - y1 = m(x - x1)
slope(m) = 1/2
(1,3)...x1 = 1 and y1 = 3
sub
y - 3 = 1/2(x - 1)
y - 3 = 1/2x - 1/2
y = 1/2x - 1/2 + 3
y = 1/2x - 1/2 + 6/2
y = 1/2x + 5/2 <=== slope intercept form
The expected value of the sample mean of the values obtained in these 300 tosses is 3.5
Given :
A fair six sided die is tossed 300 times
We have to find the expected value of the sample mean of the values obtained in these 300 tosses.
A dice have six sides:
In a fair dice every side has equal chance of occurrence,
Now the probability of presence of each side = 1/6
Now the expected value of the sample mean of the values obtained in these 300 tosses is given by:
E(x) = Σx P(x =x)
= 1*1/6 + 2*1/6 + 3*1/6 + 4*1/6 + 5*1/6 + 6*1/6
= 1/6 + 2/6 + 3/6 + 4/6 + 5/6 + 6/6
= 1/6 (1+2+3+4+5+6)
= 1/6 (21)
= 21/6
E(x) = 3.5
Hence, the expected value of the sample mean of the values obtained in these 300 tosses is 3.5
To know more about sample mean check the below link:
brainly.com/question/29739571
#SPJ4
That would be 210,000 because 767 rounds to 1000 add that to 209,000 and you get the answer of 210,000
Hope this Helped......
