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Fed [463]
3 years ago
14

Identify the vertex of the graph tell whatever it is a minimum or maximum

Mathematics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

There's no Image. I guess you forgot to send.

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What is the y-intercept of the quadratic y=-2x^2-4x-5 ?<br> (-5,0)<br> (0,-2)<br> (-1,3)<br> (0,-5)
stepan [7]
Y - intercept is f(0) then (0; m)

We have:

y=-2x^2-4x-5\to f(0)=-2(0)^2-4(0)-5=-5

Answer: (0; -5)
5 0
3 years ago
Answer both for ( brain list, thanks, 5 star review)
morpeh [17]
2/12 1/12 i hope this is clear
3 0
3 years ago
Use partial products and the distributive property to calculate the product.<br> 300 x 41.9
kolbaska11 [484]

Answer:

300*41.9=<u>12570</u>

6 0
3 years ago
What is the approximate radius of a sphere with a volume of 34 cm3?​
xz_007 [3.2K]

Answer:

<h2>2.01 cm</h2>

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

<em>R</em><em> - radius</em>

<em />

We have

V=34\ cm^3

Substitute:

\dfrac{4}{3}\pi R^3=34    <em>multiply both sides by 3</em>

3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}\pi R^3=(3)(34)

4\pi R^3=102         <em>divide both sides by 4</em>

\dfrac{4\pi R^3}{4}=\dfrac{102}{4}

\pi R^3=\dfrac{51}{2}          <em>divide both sides by π</em>

\dfrac{\pi R^3}{\pi}=\dfrac{\frac{51}{2}}{\pi}

R^3=\dfrac{51}{2\pi}   <em>use π ≈ 3.14</em>

\R^3\approx\dfrac{51}{(2)(3.14)}

R^3\approx\dfrac{51}{6.28}\\\\R^3\approx8.121\to R\approx\sqrt[3]{8.121}\\\\R\approx2.01\ cm

5 0
4 years ago
What is the approximate volume of the cone?
Vlad [161]
Volume=1/3π<span>×</span>r²×h^(Applies for any "right cone")^
Therefore your answer would be 
A.1206 cm³

8 0
3 years ago
Read 2 more answers
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