Answer:
47 rounds and Eve wins.
Step-by-step explanation:
If read right, the highest player, (player with the most tokens) has to lose 3 tokens each round, so starting off with Evelyn, 17 - 3 = 14, and the other two each have +1 added to them, so, E=14, A=17 V=16, now subtract three from A (Amelia) and don't forget that one token is always being discarded each round. So the toal number of tokens at the start was 48, (17 + 16 + 15) so right now the total tokens should be 47, which it is. now starting the second round, A gives up 3 tokens so, 17 -3, again equals 14 and each of the two other players get one token, so E=15, A=14 V=17. Now you know the general trend, so we can figure this out seeing that after each round the number of tokens decrease by one, so there will be a round till all tokens are out except one, so there will be 47 rounds and since E started with the highest number they will win.
Answer: x=1,y=0
Step-by-step explanation:
X-2y=1.....equation 1
2x-y=2.....equation 2
X=1+2y.......equation 3
Substitute equation 3into 2
2(1+2y)-y=2
2+4y-y=2
2+3y=2
3y=2-2
3y=0
Y=0/3
Y=0
Substitute for y=0 in equation 1
X-2y=1
X-2(0)=1
X-0=1
X=1
X=1 & Y=0
Answer:
slope: 0
Step-by-step explanation:
y=6
no matter what x is, y is always going to equal 6
9514 1404 393
Answer:
C, A, A
Step-by-step explanation:
In general, you ...
- identify the coefficients of one of the variables
- swap them, and negate one of them
- multiply the corresponding equations by the "adjusted" coefficients.
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In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:
multiply equation 2 by -4 . . . (eliminates x)
Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:
multiply equation 1 by 3 . . . (eliminates y)
These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.
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The other problems are worked in a similar fashion.