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Vadim26 [7]
3 years ago
9

Can someone for once ACTUALLY ANSWER THIS!I REALLY NEED HELP

Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer: r - radius of a circle

d - diagonal of a square inscribed in a circle

a - side of a square inscribed in a circle

shaded area - area of a square inscribed in a circle

The answer will basically be 9

Step-by-step explanation:

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Match the given angle pair to their relationship using the figure beloe​
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Answer:

Vertical: 1

corresponding: 3

alternate interior: 2

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What is the exponential form of 175
Serggg [28]
First factor 175:

1, 5, 5, 7

Now that we know the factors of 175, combine common factors:

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Hope this helps!
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3 years ago
Evelyn wants to estimate the percentage of people who own a tablet computer she surveys 150 indvidals and finds that 120 own a t
igomit [66]

Answer:

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

Step-by-step explanation:

Confidence interval for the proportion of people who own a tablet:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 150, \pi = \frac{120}{150} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.576.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.7159

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.8841

Percentage:

Multiply the proportion by 100.

0.7159*100 = 71.59%

0.8841*100 = 88.41%

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

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3 years ago
Alan has pound of cherries and pound of grapes.
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Step by step explanation
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