89<br> 44<br> What is the value of v?<br> V=<br> o

What is the best word to describe : a student who studies hard and improve her math grade from failing to passing

Alik [6]

Answer:

persistent

Step-by-step explanation:

3 0

2 years ago

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What is 5/8 as a percent and a decimal

Makovka662 [10]

To write a fraction as a percent, first remember that a percent is a ratio of a number to 100. If we want to write 5/8 as a percent, we need to find a fraction equivalent to 5/8 that has a 100 in the denominator. We can do this by setting up a proportion.

$\frac{5}{8}$ = $\frac{n}{100}$

<h3 /><h3>8n = 500</h3><h3>÷8 ÷8</h3><h3> n = 62.5%</h3><h3>Therefore, 5/8 is equal to 62.5%.</h3><h3 />

To write a fraction as a decimal, we can simply divide the numerator by the denominator.

5 ÷ 8 = 0.625

Therefore, 5/8 is equal to 0.625.

<h3 />

6 0

3 years ago

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct. Suppose that one of the st

Alex

Answer:

0.0111% probability that he answers at least 10 questions correctly

Step-by-step explanation:

For each question, there are only two outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent from other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct.

This means that $n = 15, p = \frac{1}{5} = 0.2$

What is the probability that he answers at least 10 questions correctly?

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.2)^{10}.(0.8)^{5} = 0.0001$

$P(X = 11) = C_{15,11}.(0.2)^{11}.(0.8)^{4} = 0.000011$

$P(X = 12) = C_{15,12}.(0.2)^{12}.(0.8)^{3} \cong 0$

$P(X = 13) = C_{15,13}.(0.2)^{13}.(0.8)^{2} \cong 0$

$P(X = 14) = C_{15,14}.(0.2)^{14}.(0.8)^{1} \cong 0$

$P(X = 15) = C_{15,15}.(0.2)^{15}.(0.8)^{0} \cong 0$

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.0001 + 0.000011 = 0.000111$

0.0111% probability that he answers at least 10 questions correctly

3 0

3 years ago

A woman has twice as many dimes as quarters in her purse. If the dimes were quarters and the quarters were dimes, she would have

Digiron [165]

If x = # of quarters, then, the # of dimes will be equal to 2x. The total value (z) would be equal to:

z = 0.25x + 0.10(2x)

Then, since you switch the quarters and the dimes, and you have a new total, the resulting equation will be:

1.2 + z = 0.25(2x) + 0.10(x)

Plug in the values you know:

1.2 + (0.25x + 0.10(2x)) = 0.25(2x) + 0.10(x)

Solve for x:

1.2 + (0.25x + 0.20x) = 0.50x + 0.10x
1.2 + 0.45x = 0.60x
1.2 = 0.15x
x = 1.2/0.15 = 8

This means that there are 8 Quarters in her bag right now. So, the amount of dimes is just 2x which is 16. So your answer will be:

She has 8 Quarters and 16 Dimes in her bag right now. Or, $3.60.

If this doesn't make sense, then tell me. I have some resources where I got the answer from to put it into simplest terms. I have the website if you want.

4 0

3 years ago

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Find m. DCR if m. RCB= 115°<br> and m_ DCB = 169º.

Burka [1]

It is 54. Draw it out. You will see that DCB - RCB = DCR

7 0

3 years ago

89 44 What is the value of v? V= o